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MrRa [10]
2 years ago
4

Conner conducts the following experiment. He places a bell in a vacuum jar. During his first trial, he leaves the bell outside t

he jar. He sees the bell vibrating and he hears the bell ringing. During his second trial, he removes the air from the vacuum jar. He sees the bell vibrating but he does not hear the abell ringing. What does this experiment tell the student about waves?
A.Light waves are electromagnetic waves and sound waves are mechanical waves.

B.Light waves are mechanical waves and sound waves are electromagnetic waves.

C.Both light waves and sound waves need a medium to travel through.

D.Neither light nor sound waves need a medium to travel through.
Chemistry
1 answer:
morpeh [17]2 years ago
8 0

Answer:

A. Light waves are electromagnetic waves and sound waves are mechanical waves.

Explanation:

The experiment is clear proof that light waves are electromagnetic waves and that sound waves are mechanical waves.

  • Electromagnetic waves are waves that do not require a material medium for their propagation.
  • Although, with material medium they can also be propagated.
  • This is why in both set up, the bell still vibrates.
  • Mechanical waves are dependent on the material in the medium.
  • They cannot be propagated in vacuum.
  • There is no matter present in vacuum to help transmit the sound waves.
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Answer:

19

Explanation:

The total distance traveled by the toy cay would be 19 cm.

The total distance traveled should not be mistaken for total displacement. While displacement measures the distance and direction from the starting position of the toy car relative to its final position, the total distance traveled is calculated by adding all the movements of the toy car together. Hence;

Total distance traveled = 9 + 4 + 6 = 19 cm

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Groups of atoms that are added to carbon backbones and give them unique properties are known as
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Answer:

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Explanation:

                   In organic chemistry they are called as Functional Group because they are the active part of a molecule. These groups give a unique characteristic to molecule both chemically and physically. Also, each functional group represent a different class of compounds.

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1                                   R--X                                             Alkyl Halides

2                                   R--OH                                          Alcohols

3                                  R--NH₂                                         Amines

4                                  R--O--R                                         Ethers

5                                   R--CO--R                                      Ketones

6                                   R--CO--H                                     Aldehydes

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8                                   R--CO--X                                     Acid Halides

10                                R--CO--NR₂                                 Acid Amides

11                                 R--CO-OR'                                  Esters

3 0
2 years ago
The density of o2 gas at 16 degrees Celsius and 1.27atm is?
velikii [3]

Answer:

The density of O₂ gas is 1.71 \frac{g}{L}

Explanation:

Density is a quantity that allows you to measure the amount of mass in a given volume of a substance. So density is defined as the quotient between the mass of a body and the volume it occupies:

density=\frac{mass}{volume}

An ideal gas is characterized by three state variables: absolute pressure (P), volume (V), and absolute temperature (T). The relationship between them constitutes the ideal gas law, an equation that relates the three variables if the amount of substance, number of moles n, remains constant and where R is the molar constant of the gases:

P * V = n * R * T

So, you can get:

\frac{n}{V} =\frac{P}{R*T}

The relationship between number of moles and mass is:

n=\frac{mass}{molar mass}

Replacing:

\frac{\frac{mass}{molar mass} }{V} =\frac{P}{R*T}

\frac{mass}{V*Molar mass} =\frac{P}{R*T}

So:

\frac{mass}{V} =\frac{P*molar mass}{R*T}

Knowing that 1 mol of O has 16 g, the molar mass of O₂ gas is 32 \frac{g}{mol}.

Then:

\frac{mass}{V} =\frac{P*molar mass of O_{2} }{R*T}

In this case you know:

  • P=1.27 atm
  • molar mass of O₂= 32 \frac{g}{mol}.
  • R= 0.0821 \frac{atm*L}{mol*K}
  • T= 16 °C=  289 °K (0°C= 273°K)

Replacing:

density=\frac{mass}{V} =\frac{1.27atm*32\frac{g}{mol}  }{0.0821\frac{atm*L}{mol*K} *289 K}

Solving:

density= 1.71 \frac{g}{L}

<u><em>The density of O₂ gas is 1.71 </em></u>\frac{g}{L}<u><em></em></u>

3 0
2 years ago
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