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ludmilkaskok [199]
1 year ago
10

A 3 kg rubber block is resting on wet concrete. The coefficient of static friction is 0.3. What is the minimum force that must b

e applied to the block to make the block begin to accelerate?
Physics
1 answer:
mrs_skeptik [129]1 year ago
8 0

Answer:

You would have to find the friction force of the rubber block which would be found with the equation of Normal force (mass*gravity) times cooeficient of friction which would give 8.82 N for the amount of friction and because you need more force than 8.82 N (assuming gravity is 9.8)

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Shear stress = 1.0 N/m² (Pa)

For water, the dynamic viscosity = 10⁻³ Pa-s at 20°C.
The velocity gradient required = (Shear stress)/(Dynamic viscosity)
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= 10³ 1/s

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2 years ago
A box slides down a frictionless plane inclined at an angle θ ¸ above the horizontal. The gravitational force on the box is dire
DedPeter [7]
<h2>Answer: at an angle \theta below the inclined plane. </h2>

If we draw the <u>Free Body Diagram</u> for this situation (figure attached), taking into account only the gravity force in this case, we will see the weight W of the block, which is directly proportional to the gravity acceleration g:  

W=m.g

This force is directed vertically at an angle \theta below the inclined plane, this means it has an X-component and a Y-component:

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Answer:

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The direction of force is towards south and the magnitude of force is 1666.67 N.

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