2 years ago

.) Identify the following quantities as scalar or vector: the mass of an object, the number of leaves on a tree, wind velocity.

Physics

2 answers:

Vladimir79 [104]2 years ago

5 0

Answer:

Explanation:

mass is a scalar quantity, number of anything is also a scalar quantity, since it lacks direction, and wind velocity is a vector quantity

VikaD [51]2 years ago

5 0

C is the answer hops this helps ;)

You might be interested in

What is the mass of an object that weighs 686N on Earth?

Oxana [17]

Answer:

70 kg is the mass of the object

Explanation:

This question can be solved with this simple formula:

Weight force = mass . gravity

686 N = mass . 9.8 m/s²

686 N / 9.8 m/s² = mass → 70 kg

Note → 1N = 1 kg . m / s²

8 0

2 years ago

An infinite conducting cylindrical shell of outer radius r1 = 0.10 m and inner radius r2 = 0.08 m initially carries a surface ch

gayaneshka [121]

Answer:

Explanation:

Solution is in the picture attached

8 0

2 years ago

Some vehicles, like _____, have different rules for registration and renewal. A. trailers B. coupes C. sedans D. pickup trucks

ycow [4]

Answer:

trailers

Explanation:

7 0

2 years ago

A standing wave of 603 Hz is produced on a string that is 1.33 m long and fixed on both ends. If the speed of the waves on this

kondaur [170]

Answer:

Explanation:

Given,

frequency of standing wave = 603 Hz

length of string,L = 1.33 m

speed of the wave, v = 402 m/s

number of antinodes = ?

Wavelength of the standing wave

$\lambda = \dfrac{v}{f}$

$\lambda = \dfrac{402}{603}$

$\lambda = 0.67\ m$

Number of anti nodes in the standing wave

$n=\dfrac{l}{\frac{\lambda}{2}}$

$n=\dfrac{2l}{\lambda}$

$n=\dfrac{2\times 1.33}{0.67}$

n =3.97= 4.

Number of antinodes is equal to 4.

7 0

2 years ago

A car of mass 875 kg is traveling 30.0 m/s when the driver applies the brakes, which lock the wheels. The car skids for 5.60 s i

AleksAgata [21]

Explanation:

It is given that,

Mass of the car, m = 875 kg

Initial speed of the car, u = 30 m/s

Brakes are applied i.e. v = 0

The car skids for 5.60 s in the positive x - direction before coming to rest, t = 5.6

(a) Acceleration of the car, $a=\dfrac{v-u}{t}$

$a=\dfrac{0-30}{5.6}$

$a=-5.35\ m/s^2$

(b) Force, F = ma

$F=875\ kg\times -5.35\ m/s^2$

F = -4681.25 N

So, the force of 4681.25 N is acting on the car.

(c) Let x is the distance covered by the car. So,

$v^2-u^2=2ax$

$0-u^2=2ax$

$x=\dfrac{-u^2}{2a}$

$x=\dfrac{-(30\ m/s)^2}{2\times -5.35\ m/s^2}$

x = 84.11 meters

So, the distance covered by the car is 84.11 meters. Hence, this is the required solution.

7 0

2 years ago