Question

A charged particle of mass 0.0040 kg is subjected to a magnetic field which acts at a right angle to its motion. If the particle moves in a circle of radius at a speed of what is the magnitude of the charge on the particle

Answer 1

Complete Question

A charged particle of mass 0.0040 kg is subjected to a 40-T magnetic field which acts at a right angle to its motion. If the particle moves in a circle of radius 0.10 m at a speed of 20m/s, what is the magnitude of the charge on the particle?

Answer:

$q=0.020C$

Explanation:

From the question we are told that:

Mass $m=0.004kg$

Magnetic field $B=40-T$

Radius $r=0.10m$

Speed $v= 20m/s$

Generally the equation for Radius of a circular path is mathematically given by

$r=\frac{p}{qB}$

Where

$p=mv$

Therefore

$q=\frac{mv}{rB}$

$q=\frac{0.004kg*20m/s}{0.1*40}$

$q=0.020C$