Question

What is the sum of 1.0566 micrometers and 0.09425 micrometers?

Answer 1

The answer to the given questions is:

1. The sum of 1.0566 micrometers and 0.09425 micrometers is 1.1509 micrometers.

2. The quantity 47.6 mL - 1.733 mL is 45.867 mL.

3. The area of a rectangular crystal surface that measures 1.34 micrometers by 0.7488 micrometers is  1.0034 μm².

4. The mass of the photo frame that is constructed from two 3.00 mm sheets of polycarbonate with measures of 28 cm by 22 cm, is 443.5 g.  

       

Let's evaluate each question.      

1. The sum of 1.0566 μm and 0.09425 μm is the following:

$x = 1.0566 \mu m + 0.09425 \mu m = 1.1509 \mu m$

Hence, the result of the sum is 1.1509 micrometers.

2. The subtraction of 47.6 mL and 1.733 mL is:

$y = 47.6 mL - 1.733 mL = 45.867 mL$

Then, the quantity 47.6 mL - 1.733 mL is 45.867 mL.

3. The area of the rectangular crystal surface is given by:

$A = l*w$

Where:

l: is the length = 1.34 μm

w: is the width = 0.7488 μm

$A = 1.34 \mu m*0.7488 \mu m = 1.0034 \mu m^{2}$

Therefore, the area of the rectangular crystal surface is 1.0034 μm².

4. The mass of the photo frame can be calculated with the equation:

$m = d*V$

Where:

d: is the density = 1.2 g/cm³

V: is the volume

The volume of a prism is:

$V = l*w*t$

Where:

t: is the thickness = 3.00 mm  

Since the photo frame is constructed from two sheets of polycarbonate, the volume is:

$V = 2(l*w*t) = 2(28 cm*22 cm*3.00 mm*\frac{1 cm}{10 mm}) = 369.6 cm^{3}$

Hence, the mass of the photo frame is:                  

$m = d*V = 1.2 g/cm^{3}*369.6 cm^{3} = 443.5 g$    

You can find more about the volume of prims here: brainly.com/question/15594686?referrer=searchResults                        

       

I hope it helps you!