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2 years ago

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An electromagnetic wave is produced by charged particles vibrating at a rate of 3.9 x 10^8 vibrations per second. the electromag

netic wave is classified as

2 answers:

77julia77 [94]2 years ago

7 0

According to sources, the most probable answer to this query is visible light. The speed of light is approximately 3 x 10^8 m/s. This is the part of the electromagnetic spectrum that we can see and perceive. Thank you for your question. Please don't hesitate to ask in Brainly your queries.

tresset_1 [31]2 years ago

7 0

Answer:

The given electromagnetic wave is a radio wave.

Explanation:

Rate of vibration of the particle or frequency of the electromagnetic wave:

frequency = $\nu=3.9\times 10^8$ vibrations per second

Wave length of the electromagnetic wave will be given by:

$\lambda =\frac{c}{\nu}$

$\lambda =\frac{3\times 10^8 m/s}{3.9\times 10^8}=0.769 m$

The wavelength of of the electromagnetic wave is lying in the range of 1 mm to 100 km that is radio wave.

Hence ,the given electromagnetic wave is a radio wave.

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A gymnast of mass 70.0 kg hangs from a vertical rope attached to the ceiling. You can ignore the weight of the rope and assume t

DiKsa [7]

Answer:

T = 686.7N

Explanation:

For this exercise we will use Newton's second law in this case there is no acceleration,

∑ F = ma

T -W = 0

The gymnast's weight is

W = mg

We clear and calculate the tension

T = mg

T = 70 9.81

T = 686.7N

3 0

1 year ago

two people are standing 100m apart on the bank of a river that flows due east. if a rock on the opposite bank is along a bearing

salantis [7]

Answer:160.88 m

Explanation:

Given

Distance Between two person is 100

i.e. $p+q=100$

Let W be the width of River

From First Triangle

$p=W\tan 24$

From Second Triangle

$q=W\tan 10$

$W\tan 24+W\tan 10=100$

$W(\tan 24+\tan 10)=100$

$W=\frac{100}{0.6215}$

$W=160.88 m$

3 0

2 years ago

A particle with a charge of +4.20nC is in a uniform electric field E⃗ directed to the left. It is released from rest and moves t

Morgarella [4.7K]

Answer:

(A). The work done is $1.50\times10^{-6}\ J$ .

(B). The potential of the starting point with respect to the endpoint is 357.14 V.

(C). The magnitude of E is 5952.38 N/C.

Explanation:

Given that,

Charge = 4.20 nC

Distance = 6.00 cm

Kinetic energy $K.E=1.50\times10^{-6}\ J$

The particle start from rest.

So, the initial kinetic energy i zero.

(A). We need to calculate the work by the electric force

Using formula of work done

$W = \Delta K.E$

$W=K.E_{f}-K.E_{i}$

Put the value into the formula

$W= 1.50\times10^{-6}-0$

$W=1.50\times10^{-6}\ J$

The work done is $1.50\times10^{-6}\ J$ .

(B). We need to calculate the potential of the starting point with respect to the endpoint

We know that.

Change in potential energy = change in kinetic energy

$\Delta P.E=\Delta K.E$

So, $U = 1.50\times10^{-6}$

Using formula of potential

$V=\dfrac{U}{q}$

Put the value into the formula

$V=\dfrac{1.50\times10^{-6}}{4.20\times10^{-9}}$

$V=357.14\ V$

The potential of the starting point with respect to the endpoint is 357.14 V.

(C). We need to calculate the magnitude of E

Using formula of work done

$W=F\times r$ ....(I)

Using formula of force

$F=qE$

Put the value in the equation (I)

$W=qE\times r$

$E=\dfrac{W}{q\times r}$

Put the value into the formula

$E=\dfrac{1.50\times10^{-6}}{4.20\times10^{-9}\times6.00\times10^{-2}}$

$E=5952.38\ N/C$

The magnitude of E is 5952.38 N/C.

Hence, This is the required solution.

7 0

2 years ago

Burning coal, which is how many power plants generate electricity, releases a number of harmful byproducts. Particulate pollutio

kiruha [24]

Answer:

$7.25\times 10^{-16}\ C$

Explanation:

F = Force = $7.25\times 10^{-11}\ N$

E = Electric field = $1\times 10^5\ N/C$

Force is given by

$F=qE$

$\Rightarrow q=\dfrac{F}{E}$

$\Rightarrow q=\dfrac{7.25\times 10^{-11}}{1\times 10^5}$

$\Rightarrow q=7.25\times 10^{-16}\ C$

The charge on the particle is $7.25\times 10^{-16}\ C$

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2 years ago

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Citrus2011 [14]

Answer:

A. Create radioactive waste i believe

Explanation:

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2 years ago

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