Answer:
B_o = 1.013μT
Explanation:
To find B_o you take into account the formula for the emf:

where you used that A (area of the loop) is constant, an also the angle between the direction of B and the normal to A.
By applying the derivative you obtain:

when the emf is maximum the angle between B and the normal to A is zero, that is, cosθ = 1 or -1. Furthermore the cos function is 1 or -1. Hence:

hence, B_o = 1.013μT
Answer:
A. Stratosphere is said to be stable layer of the atmosphere when cool air sinks and warm air rises.Due to the fact that cool air has tendency to sink ,the air is not going fluctuating up and down in the stratosphere. This means that the air remains stationary or particles remains there for a very long duration.
B. If the lifted index is negative then the parcel temperature is warmer than the actual temperature. In addition, the parcel that is less warm than the surrounding will be less dense and will rise.
C. The water vapor come from different kinds of fronts; gust fronts from existing storms as their downdraft hits the surface, spreads and lifts air in front, upper air disturbances and surface heating by solar radiation making an unbalanced vertical profile .
D. the threshold used by storm chasers to assess if the dew point temperature is high enough to produce large thunderstorms is moisture ,the surface dew point needs to be 55 degrees fahrenheit or greater for a surface based thunderstorm to occur.
E. Wind shear is the change in wind direction or speed with height in an atmosphere.
Explanation:
Answer:
The acceleration you can get with that engine in your car is around 70,56
or 7,26
using 1500kg of mass or 3306 pounds
Explanation:
Using the equation of the force that is:

So, you notice that you know the force that give the engine, so changing the equation and using a mass of a car in 1500 kg or 3306 pounds


<em> Note: N or Newton units are:
</em>

Also in pounds you can compared

Note: lf in force units are: 

Lets make the original number of nuclides at the start is 100.
If 7/8 of 100 is decayed, that means 87.5 decayed.

And there is 1/8 left of the number of nuclide 100. Which is 12.5


How many Half lifes passed for 100 to become 12.5 is 3 Half-Lives.

Each Half-Life is 80 seconds so there is 240 seconds

The answer is that it takes 240 seconds.