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timama [110]
2 years ago
12

Lee conducts an experiment to see if mass is conserved when a piece of charcoal is burned for 5.0 minutes. He measures the mass

of the charcoal before lighting it with a match. At the end of 5.0 minutes, Lee puts out the fire by suffocating it. After the charcoal has cooled, he measures its mass again. His data are below.
Initial Mass | Final Mass
.415 | .289

Charlene tries to repeat Lee's experiment by using a different piece of charcoal. But she burns the charcoal for just 3.0 minutes and collects all of the gas and dust released by the burning charcoal. She then weighs the total mass of these objects. Her results are below.
Initial Mass | Final Mass
.498 | .498
Charlene's experimental results indicate that mass was conserved. Why do Lee's results indicate that mass was not conserved?

He burned the charcoal for a longer period of time than Charlene did.

He did not collect the gas and dust released by the burning charcoal.

He forgot to measure the mass of the charcoal while it was still burning.

Mass is not conserved when an object undergoes a chemical change.
Chemistry
1 answer:
strojnjashka [21]2 years ago
3 0
Charlene conserves mass by collecting "the gas and dust released by the burning charcoal", and Lee does not . . . so the answer is . .

<u><em> . . . He did not collect the gas and dust released by the burning charcoal.</em></u>
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t_{\frac{1}{2}}=\frac{0.693}{k}

k=\frac{0.693}{82years}=8.4\times 10^{-3}years^{-1}

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t=\frac{2.303}{8.4\times 10^{-3}}\log\frac{8900}{7700}

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c

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Paraphin [41]

We are given that the balanced chemical reaction is:

cacl2⋅2h2o(aq) + k2c2o4⋅h2o(aq) ---> cac2o4⋅h2o(s) + 2kcl(aq) + 2h2o(l)

We known that the product was oven dried, therefore the mass of 0.333 g pertains only to that of the substance cac2o4⋅h2o(s). So what we will do first is to convert this into moles by dividing the mass with the molar mass. The molar mass of cac2o4⋅h2o(s) is molar mass of cac2o4 plus the molar mass of h2o.

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Looking at the balanced chemical reaction, the ratio of cac2o4⋅h2o(s) and k2c2o4⋅h2o(aq) is 1:1, therefore:

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Converting this to mass:

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3 0
2 years ago
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Answer:

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Making v the subject of the formula;

V = h /mλ

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