In determining the number of significant figures in a
given number, there are three rules to always remember / follow:
First: All integers except
zero are always significant.
<span>Second: Any zeros located between
non zeroes are always significant.</span>
Third: A zero located
after a non zero in a decimal is always significant whether it is before or
after the decimal
Therefore using this rule,
the number of significant digits in the given numbers are:
(a) 214 = 3
(b) 81.60 = 4
(c) 7.03 = 3
(d) 0.03 = 1
(e) 0.0086 = 2
(f) 3236 = 4
(g) 8700 = 2
Answer:
a) 600nm
b) 300nm
Explanation:
the path difference = 2t
t = thickness of the film
L' = wavelength of light in film = L/n
L = wavength of light in air
n = refractive index of glass
(a)
for destructive interference 2t = L'/2 = L/2n
L = 4*t*n
= 4*120*10^-9*1.25
L = 600 nm
(b)
for constructive interference 2t = L' = L/1.25
L = 2tn
= 2 × 1.25 × 120nm
= 300 nm
R= (rou * L) / area
where R is the wire resistance
rou: resistivity of the wire material
L : wire length
A : cross section area of wire
by sub.
0.757= (rou*25)/ 3.5*10^-6
25*rou = 2.6495*10^-6
rou= 1.0598*10^-7 ohm.m
Find Displacement and Distance
displacement ...
north is 700+400+100 =1200m n
south=1200m
1200-1200=0
east is 300+300=600m
west is 600m
600-600=0
back at dtart. displ zero
distance is 700+ 300m + 400 m + 600m + 1200m + 300m + 100m = 3600m
Answer:
Wavelength of incident light, 
Given:
Distance between slit and screen, x = 5.00 m
slit width, d = 0.180 mm
width of the fringe, 
Solution:
To calculate the wavelength of the incident light, 
:
