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Gnom [1K]
2 years ago
3

A car manufacturer wants to change its car’s design to increase the car’s acceleration. Which changes should the engineers consi

der making to the design?
increase the force that the engine provides
decrease the force that the engine provides
increase the mass of the car
decrease the mass of the car
increase the top velocity the car can travel
decrease the top velocity the car can travel
Physics
2 answers:
malfutka [58]2 years ago
6 0
<span>According to Newton's Second Law of Motion, Force=Mass x Acceleration. This suggests that Force is Directly Proportional to Acceleration, thus, higher the force provided by the engine, more will be the acceleration obtained. Newton's Second Law also suggests that Acceleration is Inversely Proportional to Mass, thus, lower the mass, more acceleration will be attained. Acceleration is nothing but simply the change in velocity with respect to time, which in turn means, higher the top velocity of the car more will be the acceleration. Changes to be Considered:- 1. Increase the Force provided by the Engine. 2. Decrease the Mass of the Car. 3. Increase the Top Velocity the Car can travel.</span>
tia_tia [17]2 years ago
4 0

Answer:

a and d

Explanation:

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Answer:

2\times 10^{-3}\ C

6000

1.2 J

3.33\times 10^{-6}\ F

Explanation:

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Charge is given by

Q=It\\\Rightarrow Q=1\times 2\times 10^{-3}\\\Rightarrow Q=2\times 10^{-3}\ C

The charge flowing through the electrocytes in that amount of time is 2\times 10^{-3}\ C

The maximum potential is given by

V_m=nV\\\Rightarrow n=\dfrac{V_m}{V}\\\Rightarrow n=\dfrac{600}{100\times 10^{-3}}\\\Rightarrow n=6000

The number of electrolytes is 6000

Energy is given by

E=Pt\\\Rightarrow E=V_mIt\\\Rightarrow E=600\times 1\times 2\times 10^{-3}\\\Rightarrow E=1.2\ J

The energy released when the electric eel delivers a shock is 1.2 J

Equivalent capacitance is given by

C_e=\dfrac{Q}{V_m}\\\Rightarrow C_e=\dfrac{2\times 10^{-3}}{600}\\\Rightarrow C_e=3.33\times 10^{-6}\ F

The equivalent capacitance of all the electrocyte cells in the electric eel is 3.33\times 10^{-6}\ F

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v=u+at
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