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MAVERICK [17]
1 year ago
15

The wavelength of the characteristic, bright yellow-orange flame test color of sodium is 590 nm. Calculate the average energy (Δ

E) associated with this atomic emission line.
Chemistry
1 answer:
Assoli18 [71]1 year ago
7 0
<span>The energy associated with the 590nm atomic emission line is 3.369 x 10^49 Joules. This can be determined by multiplying Plank’s constant (6.626 x 10^34 Js) by the speed of light (3x 10^8 m/s), and then dividing the result by the wavelength (590 x 10^-9 m).</span>
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How many sodium ions are in the initial 50.00-mL solution of Na2CO3
tresset_1 [31]
From other sources, the given mass of the solute that is being dissolved here is 7.15 g Na2CO3 - 10H2O. We use this amount to convert it to moles of Na2CO3 by converting it to moles using the molar mass then relating the ratio of the unhydrated salt with the number of water molecules. And by the dissociation of the unhydrated salt in the solution, we can calculate the moles of Na+ ions that are present in the solution.

Na2CO3 = 2Na+ + CO3^2-

7.15 g Na2CO3 - 10H2O (1 mol / 402.9319 g) (1 mol Na2CO3 / 1 mol Na2CO3 - 10H2O) ( 1 mol Na2CO3 / 1 mol Na2CO3-10H2O ) ( 2 mol Na+ / 1 mol Na2CO3) = 0.04 mol Na+ ions present
8 0
2 years ago
How many grams of NO are required to produce 145 g of N2 in the following reaction?
V125BC [204]

Answer:

b. 186 g

Explanation:

Step 1: Write the balanced equation.

4 NH₃(g) + 6 NO(g) → 5 N₂(g) + 6 H₂O(l)

Step 2: Calculate the moles corresponding to 145 g of N₂

The molar mass of nitrogen is 28.01 g/mol.

145g \times \frac{1mol}{28.01 g} =5.18 mol

Step 3: Calculate the moles of NO required to produce 5.18 moles of N₂

The molar ratio of NO to N₂ is 6:5.

5.18molN_2 \times \frac{6molNO}{5molN_2} = 6.22molNO

Step 4: Calculate the mass corresponding to 6.22 moles of NO

The molar mass of NO is 30.01 g/mol.

6.22mol \times \frac{30.01g}{mol} =186 g

4 0
1 year ago
What is the millimolar solubility of oxygen gas, o2, in water at 16 ∘c, if the pressure of oxygen is 1.00 atm?
Artyom0805 [142]
Partial pressure is the amount of pressure or force that is exerted by the atoms into the outer environment. it is dependent on the temperature and pressure of the present surroundings. in this case, we are asked in this problem to determine the partial pressure of oxygen at 16oC and 1 atm. We have to look into a solubility data table commonly found in handbooks and determined via experiments and correlations. According to literature, the value of the partial pressure is equal to 0.617 mM.This is under the assumption that the salinity of the water in which oxygen is dissolved is equal to zero.
8 0
1 year ago
Read 2 more answers
Repulsion of electrons within two interacting molecules produces changes in electron distribution. This change in electron distr
ycow [4]

Answer:

D

Explanation:

This explains how two noble gases molecules can have an attractive force between them.

This force is called as van dar Waals forces.

It plays a fundamental role in fields in as diverse as supramolecular chemistry structural biology .

If no other forces are present, the point at which the force becomes repulsive rather than attractive as two atoms near one another is called the van der Waals contact distance. This results from the electron clouds of two atoms unfavorably coming into contact.[1] It can be shown that van der Waals forces are of the same origin as the Casimir effect, arising from quantum interactions with the zero-point field.[2] The resulting van der Waals forces can be attractive or repulsive.[3] It is also sometimes used loosely as a synonym for the totality of intermolecular forces.[4] The term includes the force between permanent dipoles (Keesom force), the force between a permanent dipole and a corresponding induced dipole (Debye force), and the force between instantaneously induced dipoles

6 0
1 year ago
The Atomic Mass of Al is 26.98154 g/mol. Is it possible to have 5.0 × 10^-25 g of Al? Explain.
Lesechka [4]
<span>If a mole of aluminum weighs 26.98 grams, that means 1 atom of aluminum weighs = (26.98 g/mole) / (6.023 x 10^23 atoms/mole) = 4.479 x 10^-23 grams,

</span>so, it is not possible because 1 atom weighs that much we calculated which is <span>almost 100 times more than the amount you mentioned</span>

8 0
1 year ago
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