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MAVERICK [17]
1 year ago
15

The wavelength of the characteristic, bright yellow-orange flame test color of sodium is 590 nm. Calculate the average energy (Δ

E) associated with this atomic emission line.
Chemistry
1 answer:
Assoli18 [71]1 year ago
7 0
<span>The energy associated with the 590nm atomic emission line is 3.369 x 10^49 Joules. This can be determined by multiplying Plank’s constant (6.626 x 10^34 Js) by the speed of light (3x 10^8 m/s), and then dividing the result by the wavelength (590 x 10^-9 m).</span>
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Answer:

2.01

Explanation:

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Answer:

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From The equation of reaction

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0.15= 0.25*x/0.25

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