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2 years ago

What commercially available compound is used to generate cl2?

Chemistry

2 answers:

Kipish [7]2 years ago

7 0

Hello!

The commercially available compound that is used to generate Cl₂ is Sodium Hypochlorite

Sodium Hypochlorite is present in commercial bleach. Its chemical formula is NaClO.

Sodium Hypochlorite can react with acids (which can be present in vinegar, glass and window cleaners, drain cleaners or lime, calcium and rust removal products) to form Chlorine gas as shown by the following reaction (for a generic acid HA)

NaClO(aq) + HA(aq) → H₂O(aq) + Cl₂(g) + NaA(aq)

Chlorine gas is very toxic, so bleach should never be mixed with anything but water.

Have a nice day!

GuDViN [60]2 years ago

6 0

<span>Bleach and ammonia can be used to make cl2. Bleach is commercially available and so people should be very careful during these experiments or even when mixing things in the household.</span>

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Rutherford, geiger, and marsden’s experiment demonstrated that the volume of the nucleus is roughly what fraction of the volume

trasher [3.6K]

Rutherford, Geiger and Marsden's experiment proved that every atom has a nucleus and that this nucleus is of positive charge and contains the most of the mass of the atom. 0.005% of the volume occupied by the electrons is the volume of the nucleus.

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1 year ago

A sample of an unknown substance has a mass of 0.158 kg. If 2,510.0 J of heat is required to heat the substance from 32.0°C to 6

JulijaS [17]

Specific heat is the amount of heat absorb or released by a substance to change the temperature to one degree Celsius. To determine the specific heat, we use the expression for the heat absorbed by the system. Heat gained or absorbed in a system can be calculated by multiplying the given mass to the specific heat capacity of the substance and the temperature difference. It is expressed as follows:
Heat = mC(T2-T1)
By substituting the given values, we can calculate for C which is the specific heat of the material.
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8 0

2 years ago

Read 2 more answers

Ammonia (nh3(g), hf = –46.19 kj/mol) reacts with hydrogen chloride (hcl(g), hf = –92.30 kj/mol) to form ammonium chloride (nh4cl

steposvetlana [31]

Answer: The $\Delta H_{rxn}$ for the given chemical reaction is -175.51 kJ/mol

Explanation: Enthalpy change of the reaction is defined as the amount of heat released or absorbed in a given chemical reaction.

Mathematically,

$\Delta H_{rxn}=\Delta H_f_{(products)}-\Delta H_f_{(reactants)}$

We are given a chemical reaction. The reaction follows:

$NH_3(g)+HCl(g)\rightarrow NH_4Cl(s)$

$H_f_{(NH_3)}=-46.19kJ/mol$

$H_f_{(HCl)}=-92.30kJ/mol$

$H_f_{(NH_4Cl)}=-314.4kJ/mol$

Enthalpy change for the reaction of he given chemical reaction is given by:

$\Delta H_{rxn}=H_f_{(NH_4Cl)}-(H_f_{(NH_3)}+H_f_{(HCl)})$

Putting the values in above equation, we get

$\Delta H_{rxn}=-314.4-(-92.30-46.19)kJ/mol$

$\Delta H_{rxn}=-175.51kJ/mol$

8 0

2 years ago

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2CH4(g)⟶C2H4(g)+2H2(g)

Rasek [7]

Answer : The enthalpy change for the reaction is, 201.9 kJ

Explanation :

According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.

According to this law, the chemical equation can be treated as ordinary algebraic expression and can be added or subtracted to yield the required equation. That means the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.

The balanced reaction of $CH_4$ will be,

$2CH_4(g)\rightarrow C_2H_4(g)+2H_2(g)$ $\Delta H^o=?$

The intermediate balanced chemical reaction will be,

(1) $CH_4(g)+2O_2(g)\rightarrow CO_2(g)+2H_2O(l)$ $\Delta H_1=-890.3kJ$

(2) $C_2H_4(g)+H_2(g)\rightarrow C_2H_6(g)$ $\Delta H_2=-136.3kJ$

(3) $2H_2(g)+O_2(g)\rightarrow 2H_2O(l)$ $\Delta H_3=-571.6kJ$

(4) $2C_2H_6(g)+7O_2(g)\rightarrow 4CO_2(g)+6H_2O(l)$ $\Delta H_4=-3120.8kJ$

Now we will multiply the reaction 1 by 2, revere the reaction 2, reverse and half the reaction 3 and 4 then adding all the equations, we get :

(1) $2CH_4(g)+4O_2(g)\rightarrow 2CO_2(g)+4H_2O(l)$ $\Delta H_1=2\times (-890.3kJ)=-1780.6kJ$

(2) $C_2H_6(g)\rightarrow C_2H_4(g)+H_2(g)$ $\Delta H_2=-(-136.3kJ)=136.3kJ$

(3) $H_2O(l)\rightarrow H_2(g)+\frac{1}{2}O_2(g)$ $\Delta H_3=-\frac{1}{2}\times (-571.6kJ)=285.8kJ$

(4) $2CO_2(g)+3H_2O(l)\rightarrow C_2H_6(g)+\frac{7}{2}O_2(g)$ $\Delta H_4=-\frac{1}{2}\times (-3120.8kJ)=1560.4kJ$

The expression for enthalpy of the reaction will be,

$\Delta H^o=\Delta H_1+\Delta H_2+\Delta H_3+\Delta H_4$

$\Delta H=(-1780.6kJ)+(136.3kJ)+(285.8kJ)+(1560.4kJ)$

$\Delta H=201.9kJ$

Therefore, the enthalpy change for the reaction is, 201.9 kJ

5 0

1 year ago

Classify the following as a type of potential energy or kinetic energy (use the letters K or P)

Zanzabum

K, P, K, K, P, K, K, P, K, P. If it is moving, it is kinetic, if it isn't, it's potential. the sugar one is a little tricky using that method though, because we generally consider this in terms of spacial movement, but sugar holds energy which is later released by your body to allow you to move.the chemical bonds have potential energy because they release energy when broken.

5 0

1 year ago

Read 2 more answers