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Gnoma [55]
2 years ago
4

HURRY! During early research in nuclear energy, why were scientists surprised that the products from splitting a uranium nucleus

had less mass than the reactants?
1.They expected that the large release of energy would cause an increase in mass.
2.Up to that time, only chemical changes were known to form less mass than they started with.
3.All known changes always started and ended with the same amount of mass.
4.Other known nuclear changes resulted in the same mass of products as reactants.
Physics
2 answers:
FrozenT [24]2 years ago
7 0

i think it is the 3rd one....

Yakvenalex [24]2 years ago
6 0

Answer: 3. All known changes always started and ended with the same amount of mass.

Explanation:

From the law of conservation of mass, all the changes started and ended with same amount of mass. The mass could not be formed or destroyed.

Later on it was found that mass could convert to energy and vice-versa via relation:

E = m c² ( Einstein's mass-energy relation)

Thus, early research in nuclear energy brought surprise. The lack of mass in the products was actually converted to an equivalent amount of energy.

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A physics student stands on the rim of the canyon and drops a rock. The student measures the time for it to reach the bottom to
madam [21]

Answer:

Canyon is 50.176 meter deep.

Explanation:

The students is standing on the rim of the canyon and drops down a rock from the rim(cliff). We have to find what is the depth of the canyon i.e. how much below is the ground from the cliff.

Given data:

Time = t = 3.2 s

Initial velocity = v_{i} = 0 m/s

Gravitational acceleration = g = 9.8 m/s²

Height = h = ?

According to second equation of motion

h = v_{i}t + \frac{1}{2}gt^{2}

As initial velocity is zero, So the first term of right hand side of above equation equal to zero

h = \frac{1}{2}gt^{2}

h = (0.5)(9.8)(3.2)²

h = 50.176 m

This means, the rock traveled 50.176 meters to reach the bottom of the Canyon. So, the Canyon is 50.176 meter deep.

5 0
2 years ago
A brick is resting on a rough incline as shown in the figure. The friction force acting on the brick, along the incline, is
Tasya [4]
B) equal to the gravitational force of the brick
6 0
2 years ago
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Hydrogen peroxide is sold commercially as an aqueous solution in brown bottles to protect it from light. Calculate the longest w
snow_lady [41]

Explanation:

Below is an attachment containing the solution

5 0
2 years ago
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Tyler stands at rest on a skateboard. He has a mass of 120 kg. His friend (m = 60 kg) jumps into his arms at a speed of 2 m/s. I
Andrews [41]
Momentum question. This is an inelastic collision, so 

m1v1+m2v2=Vf(m1+m2)
Vf=(m1v1+m2v2)/(m1+m2)=[(120kg)(0m/s)+(60kg)(2m/s)] / (120kg+60kg)
Vf=120kg m/s  /   180kg
Vf=0.67m/s

0.67m/s
5 0
2 years ago
You are participating in a NASA traineeship, working with a group planning a new landing on Mars. Your supervisor has come up wi
aivan3 [116]

Answer:

h=17005.8 km

Explanation:

Newton's law of universal gravitation states that the force experimented by a satellite of mass m orbiting Mars, which has mass M=6.39\times10^{23} kg at a distance r will be:

F=\frac{GMm}{r^2}

where G=6.67\times10^{-11}Nm^2/kg^2 is the gravitational constant.

This force is the centripetal force the satellite experiments, so we can write:

F=ma_{cp}=mr\omega^2=mr(\frac{2\pi}{T})^2=\frac{4\pi^2mr}{T^2}

Putting all together:

\frac{GMm}{r^2}=\frac{4\pi^2mr}{T^2}

which means:

r=\sqrt[3]{\frac{GM}{4\pi^2}T^2}

Which for our values is:

r=\sqrt[3]{\frac{(6.67\times10^{-11}Nm^2/kg^2)(6.39\times10^{23} kg)}{4\pi^2}(1.026\times24\times60\times60s)^2}=20395282m=20395.3km

Since this distance is measured from the center of Mars, to have the height above the Martian surface we need to substract the radius of Mars R=3389.5 km , which leaves us with:

h=r-R=20395.3km-3389.5 km=17005.8 km

6 0
2 years ago
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