Answer:
Explanation:
b ) First is concave lens with focal length f₁ = - 12 cm .
object distance u = - 20 cm .
Lens formula
1 / v - 1 / u = 1 / f
1 / v + 1 / 20 = -1 / 12
1 / v = - 1 / 20 -1 / 12
= - .05 - .08333
= - .13333
v = - 1 / .13333
= - 7.5 cm
first image is formed before the first lens on the side of object.
This will become object for second lens
distance from second lens = 7.5 + 9 = 16.5 cm
c )
For second lens
object distance u = - 16.5 cm
focal length f₂ = + 12 cm ( lens is convex )
image distance = v
lens formula ,
1 / v - 1 / u = 1 / f₂
1 / v + 1 / 16.5 = 1 / 12
1 / v = 1 / 12 - 1 / 16.5
= .08333- .0606
= .02273
v = 1 / .02273
= 44 cm ( approx )
It will be formed on the other side of convex lens
distance from first lens
= 44 + 9 = 53 cm .
magnification by first lens = v / u
= -7.5 / -20 = .375 .
magnification by second lens = v / u
= 44 / - 16.5
= - 2.67
d )
total magnification
= .375 x - 2.67
= - 1.00125
height of final image
= 2.50 mm x 1.00125
= 2.503mm
e )
The final image will be inverted with respect to object because total magnification is negative .
Answer:
Average density of Sun is 1.3927 
.
Given:
Radius of Sun = 7.001 ×
km = 7.001 ×
cm
Mass of Sun = 2 × 
kg = 2 × 
g
To find:
Average density of Sun = ?
Formula used:
Density of Sun = 
Solution:
Density of Sun is given by,
Density of Sun =
Volume of Sun = 
Volume of Sun = ![\frac{4}{3} \times 3.14 \times [7.001 \times 10^{10}]^{3}](https://tex.z-dn.net/?f=%5Cfrac%7B4%7D%7B3%7D%20%5Ctimes%203.14%20%5Ctimes%20%5B7.001%20%5Ctimes%2010%5E%7B10%7D%5D%5E%7B3%7D)
Volume of Sun = 1.436 × 
Density of Sun = 
Density of Sun = 1.3927
Thus, Average density of Sun is 1.3927 .
R = 0.407Ω.
The resistance R of a particular conductor is related to the resistivity ρ of the material by the equation R = ρL/A, where ρ is the material resistivity, L is the length of the material and A is the cross-sectional area of the material.
To calculate the resistance R of a wire made of a material with resistivity of 3.2x10⁻⁸Ω.m, the length of the wire is 2.5m and its diameter is 0.50mm.
We have to use the equation R = ρL/A but first we have to calculate the cross-sectional area of the wire which is a circle. So, the area of a circle is given by A = πr², with r = d/2. The cross-sectional area of the wire is A = πd²/4. Then:
R =[(3.2x10⁻⁸Ω.m)(2.5m)]/[π(0.5x10⁻³m)²/4]
R = 8x10⁻⁸Ω.m²/1.96x10⁻⁷m²
R = 0.407Ω
Impulse is equal to change in momentum. So if impulse is 2000 then to solve for new velocity we just set it equal to equation for momentum.
First find original momentum by p=mv
p=1000*20=20000
So then taking that value minus the impulse since it was in opposite direction of original momentum it will slow it down some. To find new velocity we just take
20000-2000=18000=mv
v=18000/1000 =18m/s
Hope this helps!! Any questions please ask!!
Thank you!
Answer:
The speed is 173 m/s.
Explanation:
Given that,
A = 47
B = 14
Length 1 urk = 58.0 m
An hour is divided into 125 time units named dorts.
3600 s = 125 dots
dorts = 28.8 s
Speed v= (25.0+A+B) urks/dort
We need to convert the speed into meters per second
Put the value of A and B into the speed
Hence, The speed is 173 m/s.
