Answer:
Explanation:
1. Calculate the molar mass of N₂H₄
2N = 2 × 14 = 28
4H = 2 × 1 = <u> 4</u>
Tot. = 32
2. Calculate the mass percent of N
Answer:
A) coenzyme A
Explanation:
The NADH and FADH₂ are the energy rich molecules which are formed in the processes like glycolysis, TCA cycle and the fatty acid oxidation as they contain pair of electrons which have very high transfer potential.
As a result of the energy produced when these molecules transfer their electrons to the oxygen , ATP is generated by a series of electron carriers which collectively is called electron transport chain (ETC).
<u>The components of chain include Fe–S centers, Non-heme, FMN, coenzyme Q, and cytochromes .
</u>
The energy derived from the transfer of electrons is used to pump the protons across mitochondrial membrane.
As a result, an electrochemical gradient is generated which results in some energy which is then harnessed by the ATP synthase to form ATP.
<span>Melting is an endothermic process (i.e. it absorbs heat), whereas freezing is an exothermic process (i.e. it releases heat, or can be thought of, albeit incorrectly from a thermodynamics standpoint, as "absorbing cold"). The standard enthalpy of fusion of water can be used for both scenarios, but standard enthalpy is in units of energy/mass, so 10 times as much energy will be absorbed in the former scenario (melting 10 kg of ice) than what will be absorbed in the latter scenario (freezing 1 kg of water). For both processes, assuming the water is pure and at standard atmospheric pressure, and the entire mass remains at thermal equilibrium, the temperature of both the solid and the liquid will remain at precisely 0 degrees Celsius (273 K) for the duration of the phase change.</span>
Given that there is 48 liters of gasoline to be burned and that 45 kJ of energy is released per gram of gasoline burned, the amount of energy that the gasoline fuel produces can then be calculated, First, we convert 48 liters of gasoline to units of mass (grams) in order to use the given conversion of 45 kJ per gram of gasoline. To do this, we use the density of gasoline which is 0.77 g/mL. The following expression is then used:
48 L gasoline x 1000 mL/L x 0.77 g/mL x 45 kJ/g gasoline = 1663200 kJ
<span>The amount of energy produced by burning 48 L of gasoline was then determined to be 1663200 kJ. </span>
