All categories

2 years ago

Why are the outlets in homes never wired in series? What problems might this present?

Physics

2 answers:

Yuri [45]2 years ago

7 0

Answer:

It would be more uncomfortable to use electricity in your house as all the outlets must be connected to appliances so the electricity can flow.

Explanation:

Series circuits in real-life

Time ago christmas lights were wired in series, it means electricity flowed in one single way through all the bulbs. The problem was when one of those many bulbs stopped working because it interrupmted the only path for eletricity and all the bulbs turned off as only one of them is broken. Very annoying, isn't it? Now lets repeat the example imagining the outlets of your livingroom connected in series. Let say you have 4 outlets connected in series. The main problem is that each one of those outlets works as a broken bulb as long as no appliance is connected because electricity must flow from the first outlet to appliance and then it will go to the second outlet and so on until reaching the 4th outlet and the 4th appliance. It works that way because there is only one way for electriciy to flow through the 4 outlets. pretty unpractical, isn't it? let see a better solution

Parallel outlets

The good thing about parallel outlets is that they are directly connected to the power supply and the only element that is necessary to let the electricity fllow is the appliance. Each outlet is part of a different way (a different circuit) so you can manage your outlets separately. Attached you will find a picture to ilustrate this better. Remember that each outlet in series works exactly like a broken bulb. If you have any doubts, just let me know.

rosijanka [135]2 years ago

3 0

A series circuit means that there is only one current. Which means that everything is sharing that one wire. Homes are normally wired with a parallel circuit, which means that there is more than one current running through the house. If you have a series, if you turn on one thing for example a light switch, than everything will turn on with it. But of you have a parallel you can turn on everything one by one, and save energy.

Trust me. I just took my semester test in physical science this morning, and I passed. This is exactly what we learned. <span />

You might be interested in

You are piloting a helicopter which is rising vertically at a uniform velocity of 14.70 m/s. When you reach 196.00 m, you see Ba

Cloud [144]

Answer:

The ball reaches Barney head in $t = 8 \ s$

Explanation:

From the question we are told that

The rise velocity is $v = 14.70 \ m/s$

The height considered is $h = 196 \ m$

The horizontal velocity of the large object is $v_h = 8.50 \ m/s$

Generally from kinematic equation

$s = ut + \frac{1}{2} gt^2$

Here s is the distance of the object from Barney head ,

u is the velocity of the object along the vertical axis which is equal but opposite to the velocity of the helicopter

$u = -14.7 m/s$

$196 = -14.7 t + \frac{1}{2} * 9.8 * t^2$

= $4.9 t^2 - 14.7t - 196 = 0$

Solving the above equation using quadratic formula

The value of t obtained is $t = 8 \ s$

6 0

2 years ago

Which statement is not a good practice when working inside a computer case?

lozanna [386]

Answer:

a. be sure to hold expansion cards by the edge connectors

Explanation:

Removal of loose jewelry is a good safety practice. Also not touching a microchip with a magnetized screwdriver is also a good practice.

But holding expansion cards by the edge connectors is not a good practice, so it is the odd one in the question. Therefore answer option a provides the correct and best answer to the question

3 0

2 years ago

If a rock is thrown upward on the planet mars with a velocity of 11 m/s, its height (in meters) after t seconds is given by h =

Butoxors [25]

(a) 3.56 m/s
(b) 11 - 3.72a
(c) t = 5.9 s
(d) -11 m/s
For most of these problems, you're being asked the velocity of the rock as a function of t, while you've been given the position as a function of t. So first calculate the first derivative of the position function using the power rule.
y = 11t - 1.86t^2
y' = 11 - 3.72t
Now that you have the first derivative, it will give you the velocity as a function of t.
(a) Velocity after 2 seconds.
y' = 11 - 3.72t
y' = 11 - 3.72*2 = 11 - 7.44 = 3.56
So the velocity is 3.56 m/s
(b) Velocity after a seconds.
y' = 11 - 3.72t
y' = 11 - 3.72a
So the answer is 11 - 3.72a
(c) Use the quadratic formula to find the zeros for the position function y = 11t-1.86t^2. Roots are t = 0 and t = 5.913978495. The t = 0 is for the moment the rock was thrown, so the answer is t = 5.9 seconds.
(d) Plug in the value of t calculated for (c) into the velocity function, so:
y' = 11 - 3.72a
y' = 11 - 3.72*5.913978495
y' = 11 - 22
y' = -11
So the velocity is -11 m/s which makes sense since the total energy of the rock will remain constant, so it's coming down at the same speed as it was going up.

3 0

2 years ago

In a certain region of space, a uniform electric field has a magnitude of 4.30 x 104 n/c and points in the positive x direction.

denis23 [38]

The magnetic force exerted by a field E to a charge q is given by F=Eq. In this case, F=4.30*10^4*(6.80mu C). 1mu C=10^-6C, so F=4.30*6.80=10^-2=0.29N. The direction is in the x direction, the direction that the field is applied because the charge is positive.

5 0

2 years ago

Irrigation channels that require regular flow monitoring are often equipped with electromagnetic flowmeters in which the magneti

san4es73 [151]

A) $1.36\cdot 10^{-4}T$