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2 years ago

Why are the outlets in homes never wired in series? What problems might this present?

Physics

2 answers:

Yuri [45]2 years ago

7 0

Answer:

It would be more uncomfortable to use electricity in your house as all the outlets must be connected to appliances so the electricity can flow.

Explanation:

Series circuits in real-life

Time ago christmas lights were wired in series, it means electricity flowed in one single way through all the bulbs. The problem was when one of those many bulbs stopped working because it interrupmted the only path for eletricity and all the bulbs turned off as only one of them is broken. Very annoying, isn't it? Now lets repeat the example imagining the outlets of your livingroom connected in series. Let say you have 4 outlets connected in series. The main problem is that each one of those outlets works as a broken bulb as long as no appliance is connected because electricity must flow from the first outlet to appliance and then it will go to the second outlet and so on until reaching the 4th outlet and the 4th appliance. It works that way because there is only one way for electriciy to flow through the 4 outlets. pretty unpractical, isn't it? let see a better solution

Parallel outlets

The good thing about parallel outlets is that they are directly connected to the power supply and the only element that is necessary to let the electricity fllow is the appliance. Each outlet is part of a different way (a different circuit) so you can manage your outlets separately. Attached you will find a picture to ilustrate this better. Remember that each outlet in series works exactly like a broken bulb. If you have any doubts, just let me know.

rosijanka [135]2 years ago

3 0

A series circuit means that there is only one current. Which means that everything is sharing that one wire. Homes are normally wired with a parallel circuit, which means that there is more than one current running through the house. If you have a series, if you turn on one thing for example a light switch, than everything will turn on with it. But of you have a parallel you can turn on everything one by one, and save energy.

Trust me. I just took my semester test in physical science this morning, and I passed. This is exactly what we learned. <span />

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A light ray strikes a plane mirror at an angle of 23° to the normal. What is the angle between the reflected ray and the mirror?

tiny-mole [99]

Answer: $67^{\circ}$

Explanation:

Given

Ray of light incident on plane making an angle of $23^{\circ}$ with normal

Thus incident angle $i=23^{\circ}$

So according to the law of incidence is equal to angle of reflection

$\angle i=\angle r$

thus $\angle r=23^{\circ}$

and angle between mirror and reflected ray $=90^{\circ}-23^{\circ}$

$=67^{\circ}$

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2 years ago

Four wires are made of the same highly resistive material, cut to the same length, and connected in series. Wire 1 has resistanc

Paraphin [41]

Answer:

$V_2 = \frac{R_2 V_0}{R_1+R_2+R_3+R_4}$

Explanation:

The 4 wires are connected in series: this means that the same current flow through them, and the voltage of the battery, V0, is equal to the sum of the voltages on each individual resistor:

$V_0=V_1+V_2+V_3+V_4$

Also, the equivalent resistance of the series circuit is

$R_{eq}=R_1+R_2+R_3+R_4$

The voltage V2 across wire 2 is given by Ohm's law:

$V_2 = R_2 I$ (1)

where I is the total current in the circuit, which is given by:

$I=\frac{V_0}{R_{eq}}=\frac{V_0}{R_1+R_2+R_3+R_4}$

Substituting this into eq. (1), we find an expression for V2:

$V_2 = \frac{R_2 V_0}{R_1+R_2+R_3+R_4}$

8 0

2 years ago

Which of these properties of an object best quantifies its inertia: velocity, acceleration, volume, mass, or temperature?

LuckyWell [14K]

Answer:

Mass

Explanation:

Inertia is essentially an object's tendency to stay in motion or at rest unless it is forced to do otherwise (pun intended). It only makes sense to me that mass would best quantify an object's inertia, because an object with more mass would be harder to move and/or stop from moving.

3 0

2 years ago

What is the final position of the object if its initial position is x = 0.40 m and the work done on it is equal to 0.21 J? What

r-ruslan [8.4K]

Answer:

a) Final position is x = 0.90 m

b) Final position is x = 0.133 m

Explanation:

The workdone between two points is usually approximated as the area under the force-distance curve between those two points.

From the graph,

As at the initial position, x = 0.40 m and the corresponding F = 0.8 N,

The area from that point onwards up to the end of that particular bar = 0.8 (0.5 - 0.4) = 0.08 J

The next bar has force = 0.4 N and the width of the bar = (0.75 - 0.50) = 0.25 m

Work done under this bar = 0.4 × 0.25 = 0.1 J

Total work done from the starting position up to this point now = 0.08 + 0.1 = 0.18 J, still less than 0.21 J

So, the final position has to be on the last bar. Let the position be x. The force on the last bar = 0.2 N

0.21 = 0.18 + 0.2 (x - 0.75)

0.03 = 0.2x - 0.15

0.2x = 0.18

x = 0.9 m

Therefore, the final position of the object, to do 0.21 J worth of work, starting from x = 0.4 m is 0.90 m.

b) For this part, negative work is done, this means, we will move in the negative direction to try and trace this total work done.

From the starting point where the initial position is 0.40 m, the force here is 0.80 N

The workdone under this bar to the left is

The workdone = 0.8 (0.25 - 0.4) = - 0.12 J

Since we're tracing -0.19 J, the final position has to be on the last bar (on the left), Let the position be x. The force on the last bar on the left (could also be referred to as the first bar) = 0.60 N

- 0.19 = -0.12 + 0.6 (x - 0.25)

-0.07 = 0.6x - 0.15

0.6x = 0.08

x = (0.08/0.6) = 0.133 m

Therefore, the final position of the object, after doing -0.19 J worth of work, starting from x = 0.4 m is 0.133 m.

Hope this Helps!!!