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diamong [38]
2 years ago
6

When a 4 g peanut is burned, it warms 300 ml of water 45 °c. what was the energy content of the peanut?

Chemistry
1 answer:
ryzh [129]2 years ago
7 0
Answer is: 13500 cal.
m(water) = V(water)·d(water) = 300ml·1g/ml = 300g.
ΔT = 45°C, temperature change.
<span>Calorie is amount of </span>energy<span> (heat) needed to increase the temperature of one </span>gram<span> of </span>water by 1°<span>C.
</span><span>To raise the temperature of 300 grams of water for 45°C:
</span>Heat in calories = mass in gram x temperature change °C  x specific heat (cal / gram·°C). Q = m·ΔT·c.
Q = 300g · 45°C · 1cal/g·°C = 13500 cal.
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2 years ago
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