All categories

2 years ago

Which one of the atoms shown would be most likely to form a cation with a charge of 1?

2 answers:

6 0

Ions are stable atoms of elements formed when original atoms loose or gain electrons to form stable configuration. Anions are negatively charged ions formed when atoms gain electrons while cations are the positively charged ions formed when atoms loose electrons. In this case a charge of +1 means an atom lost one electron to form a stable configuration. Therefore, the correct answer is A

Dafna1 [17]2 years ago

6 0

If I am referring to correct picture then
A. Has Four atoms in outer ring
B. Has Five atoms in outer ring
C. Has Six atoms in outer ring
D. Has Seven atoms in outer ring
E. Has Eight atoms in outer ring
Answer is A
Now we know that an atom wants to complete its outer shell while keeping electrons in pairs of two now in A there are four electrons which which can be ejected while in B will want to accept 3 electrons to complete its shell as ejecting five will take lot of energy similar case will be for C,D and E which would want to accept 2,1,0 electrons respectively

You might be interested in

Suppose that magnesium would react exactly the same as copper in this experiment. how many grams of magnesium would have been us

Vikentia [17]

The solution for this problem would be:

We are looking for the grams of magnesium that would have been used in the reaction if one gram of silver were created. The computation would be:

1 g Ag (1 mol Mg) (24.31 g/mol) / (2mol Ag)(107.87g/mol) = 0.1127 grams of Magnesium

6 0

2 years ago

Explain why calcium combines in a different ratio to a fluoride ion versus an oxide ion.

jok3333 [9.3K]

Answer:

This is due the different charges of fluoride and oxide ions.

Explanation:

When calcium reacts it is oxidized to Ca²⁺. In the same way, fluoride ion is reduced to F⁻ and oxide ion to O²⁻.

When these ions are combined, the molecule must be neutral. That means 2 ions of F⁻ are necessaries and just 1 O²⁻ ion will reacts producing:

CaF₂ and CaO.

The different charges of these ions is the reason why calcium will combine in different ratios.

5 0

2 years ago

Which of the following mixtures, with each component present at a concentration of 0.1 M, has a pH closest to 7? O A. HCIO(aq) a

eduard

for HClO, pKa = 7.54

for HNO_2, pKa = 3.15

for CH3 COOH, pKa = 4.74

Explanation:

The concentration of the solution given is 0.1 M has a pH closest to 7

The mixtures are weak acids and their salts except

HNO_3 and NaNO_3 pH = pH is near to '1'

for buffers( acidic) pH = pKa + log [salt] / [acid]

therefore [salt] = [acid] = 0.1 pH = pKa + log 0.1 / 0.1 = pKa

pH = pKa

for HClO, pKa = 7.54

for HNO_2, pKa = 3.15 therefore HClO and NaclO

mixture hs a pH closest to '7'

for CH3 COOH, pKa = 4.74

5 0

2 years ago

Read 2 more answers

A 0.580 g sample of a compound containing only carbon and hydrogen contains 0.480 g of carbon and 0.100 g of hydrogen. At STP, 3

Sati [7]

Answer:

Molecular formula for the gas is: C₄H₁₀

Explanation:

Let's propose the Ideal Gases Law to determine the moles of gas, that contains 0.087 g

At STP → 1 atm and 273.15K

1 atm . 0.0336 L = n . 0.082 . 273.15 K

n = (1 atm . 0.0336 L) / (0.082 . 273.15 K)

n = 1.500 × 10⁻³ moles

Molar mass of gas = 0.087 g / 1.500 × 10⁻³ moles = 58 g/m

Now we propose rules of three:

If 0.580 g of gas has ____ 0.480 g of C _____ 0.100 g of C

58 g of gas (1mol) would have:

(58 g . 0.480) / 0.580 = 48 g of C

(58 g . 0.100) / 0.580 = 10 g of H

48 g of C / 12 g/mol = 4 mol

10 g of H / 1g/mol = 10 moles

7 0

2 years ago

If 2.38 mol of a gas has a volume of 120.0 mL, what is the volume of 1.97 mol of the gas at the same temperature and pressure?

Gwar [14]

According to the Avogadro's law, equal volumes of all gases contain equal number of moles under the same conditions of temperature and pressure.

Here the initial volume, $V_{1} = 120.0 mL$

Initial moles of the gas, $n_{1}=2.38 mol$

Final volume of the gas $V_{2} = ?$

Final moles of the gas $n_{2}= 1.97 mol$

Plugging in the Avogadro's equation,

$\frac{V_{1}}{n_{1}} = \frac{V_{2}}{n_{2}}$

$\frac{120.0 mL}{2.38 mol} = \frac{V_{2}}{1.97 mol}$

$V_{2} = 99.33 mL$

Therefore the 1.97 mol of the gas occupies 99.33 mL at constant temperature and pressure.

7 0

2 years ago