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2 years ago

Which of the following statements describes an interaction between the geosphere and atmosphere?

Physics

2 answers:

german2 years ago

8 0

B is the answer, I’m really good at this subject

Misha Larkins [42]2 years ago

4 0

Answer:

Option (A)

Explanation:

Wind is created due to the pressure difference and it blows from a region of higher pressure to a region of low pressure.

Atmosphere refers to the envelope of gases that surrounds the earth. It is comprised of various types of gases which are present in various amount.

The wind blowing away sand in a desert environment describes the interaction between the geosphere and the atmosphere as the wind is a part of the atmosphere and the sand is a part of the geosphere.

Hence, the correct answer is option (A).

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Armand is monitoring a large sealed tank by way of a sensor that records the liquid level over time on a graph. He looks at the

timofeeve [1]

Answer:

i need ppoints

Explanation:

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1 year ago

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(YOU WILL GET BRAINLIEST)Matter may be classified as a pure substance or a mixture. Where on the Venn diagram would you insert t

inessss [21]

I think it would be B because it is matter, since it has atoms, and it contains subatomic particles, which are smaller than atoms

3 0

1 year ago

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A ball is falling at terminal velocity. Terminal velocity occurs when the ball is in equilibrium and the forces are balanced. Wh

Greeley [361]

Answer:

A free body diagram with 2 forces: the first pointing downward labeled F Subscript g Baseline 20 N and the second pointing upward labeled F Subscript air Baseline 20 N.

Explanation:

This is because at terminal velocity, the ball stops accelerating and the net force on the ball is zero. For the net force to be zero, equal and opposite forces must act on the ball, so that their resultant force is zero. That is F₁ + F₂ = 0 ⇒ F₁ = -F₂

Since F₁ = 20 N, then F₂ = -F₁ = -20 N

So, if F₁ points upwards since it is positive, then F₂ points downwards since it is negative.

So, a free body diagram with 2 forces: the first pointing downward labeled F Subscript g Baseline 20 N and the second pointing upward labeled F Subscript air Baseline 20 N best describes the ball falling at terminal velocity.

4 0

2 years ago

Read 2 more answers

A baseball thrown at an angle of 60.0° above the horizontal strikes a building 16.0 m away at a point 8.00 m above the point fro

yanalaym [24]

Answer:

a) $v_{o} =16m/s$

b) $v=9.8m/s$

c) $\beta =-35.46º$

Explanation:

From the exercise we know that the ball strikes the building 16m away and its final height is 8m more than the initial

Being said that, we can calculate the initial velocity of the ball

a) First we analyze its horizontal motion

$x=v_{ox}t$

$x=v_{o}cos(60)t$

$v_{o}=\frac{x}{tcos(60)}=\frac{16m}{tcos(60)}$ (1)

That would be our first equation

Now, we need to analyze its vertical motion

$y=y_{o}+v_{oy}t+\frac{1}{2}gt^2$

$y_{o}+8=y_{o}+v_{o}sin(60)t-\frac{1}{2}(9.8)t^2$

Knowing $v_{o}$ in our first equation (1)

$8=\frac{16}{tcos(60)}sin(60)t-\frac{1}{2}(9.8)t^2$

$\frac{1}{2}(9.8)t^2=16tan(60)-8$

Solving for t

$t=\sqrt{\frac{2(16tan(60)-8)}{9.8} } =2s$

So, the ball takes to seconds to get to the other building. Now we can calculate its initial velocity

$v_{o}=\frac{16m}{(2s)cos(60)}=16m/s$

b) To find the magnitude of the ball just before it strikes the building we need to calculate its x and y components

$v_{x}=v_{ox}+at=16cos(60)=8m/s$

$v_{y}=v_{oy}+gt=16sin(60)-(9.8)(2)=-5.7m/s$

So, the magnitude of the velocity is:

$v=\sqrt{v_{x}^{2}+v_{y}^{2}}=\sqrt{(8m/s)^2+(-5.7m/s)^2}=9.8m/s$

c) The direction of the ball is:

$\beta=tan^{-1}(\frac{v_{y} }{v_{x}})=tan^{-1}(\frac{-5.7}{8})=-35.46º$

4 0

2 years ago

For each of the following systems and time intervals, select the appropriate version of

Ahat [919]

The heating coils in you toaster during the first five seconds after you turn the toaster on is Δ K = W + Q.

Your automobile just before you fill it with gas until you pull away from the gas station at speed v is ΔK + ΔU + ΔEint = W + Q + TMW + TMT

your body while you sit quietly and eat a peanut butter and jelly sandwich for lunch is ΔEint = Q + TET + TER
 

your home during five minutes of a sunny afternoon while the temperature in the home remains fixed is ΔU = W + Q + TMW + TMT

4 0

2 years ago