Which of the following statements describes an interaction between the geosphere and atmosphere?
2 answers:
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Heat engines were developed during industrial revolution.
Generally a heat engine contains three parts i.e source, sink and working substance.
The source of a heat engine is present at a higher temperature as compared to the sink. Due to the temperature difference, the heat will flow from source to sink through working substance.
Let us consider are the temperature of source and sink.
As the source is at higher temperature as compared to sink, heat will flow from source to sink.
are the heat provided by source and heat rejected to sink.
Hence, the work done by the working substance will be -
The efficiency of a heat engine is defined as the ratio of output to the input energy.
Here output = workdone [W]
Hence, the efficiency of a heat engine is calculated as -
This is the expression for the efficiency of heat engine.
Here, all the heat absorbed by the working substance can not be converted to desired output. The efficiency of a heat engine can not be 100 percent. Some amount of heat is lost in the form of sound and heat due to the friction which is produced due to the relative motion between various parts of the machine.
Complete Question
The complete question is shown on the first and second uploaded image
Answer:
The power created is
Explanation:
From the question we are told that
The that the average power is mathematically represented as
Where W is is the Workdone which is mathematically represented as
Where F is the applies force and s is the displacement due to the force
So
Now this displacement can be represented mathematically as
Where is the average velocity and
is the time taken
So
=>
Answer:
Distance between peak height (vertically) of projectile and mountain height = (2975.2 - 1800) = 1175.2 m
Distance between where the projectile lands and ship B = (3188.8 - 3110) = 8.8 m
Explanation:
Given the velocity and angle of shot of the projectile, one can calculate the range and maximum height attained by the projectile.
H = (v₀² Sin²θ)/2g
v₀ = initial velocity of projectile = 2.50 × 10² m/s = 250 m/s
θ = 75°, g = 9.8 m/s²
H = 250² (Sin² 75)/(2 × 9.8) = 2975.2 m
Range of projectile
R = v₀² (sin2θ)/g
R = 250² (sin2×75)/9.8
R = 250² (sin 150)/9.8 = 3188.8 m
Height of mountain = 1.80 × 10³ = 1800 m
Maximum height of projectile = 2975.2 m
Distance between peak height (vertically) of projectile and mountain height = 2975.2 - 1800 = 1175.2 m
Distance of ship B from ship A = 2.5 × 10³ + 6.1 × 10² = 2500 + 610 = 3110 m
Range of projectile = 3188.8 m
Distance between where the projectile lands and ship B = 3188.8 - 3110 = 8.8 m
