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xenn [34]
2 years ago
13

The highest element in the hierarchical breakdown of the wbs is

Physics
1 answer:
Makovka662 [10]2 years ago
5 0
Work package. Hope this helps!
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Juan was wearing a bright red shirt in a very dark room. What color did his shirt appear to the people with him in the room? A)
ikadub [295]
It would appear black.   

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Charge: A piece of plastic has a net charge of +2.00 μC. How many more protons than electrons does this piece of plastic have? (
snow_lady [41]

Answer

given,

net charge = +2.00 μC

we know,

1 coulomb charge =  6.28 x 10¹⁸electrons

1 micro coulomb  charge =  6.28 x 10¹⁸ x 10⁻⁶ electron

                                         = 6.28 x 10¹² electrons

2.00 μC = 2 x 6.28 x 10¹² electrons

              = 1.256 x 10¹³ electrons

since net charge is positive.

The number of protons should be 1.256 x 10¹³ more than electrons.

hence, +2.00 μC have 1.256 x 10¹³ more protons than electrons.

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2 years ago
How far could a rabbit run if it ran 36km/h for 5.0min?
Korolek [52]

3 kilometers, it is just 5/60 or 1/12 multiplied by 36.

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2 years ago
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Ronald likes to use his erector set more than anything else.
Rashid [163]
C: Foreclosure. People in identity foreclosure have committed to an identity too soon. Often they have simply adopted the identity of a parent, close relative or respected friend.
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Bricks and insulation are used to construct the walls of a house. The
ira [324]

Answer:

\dot Q=350.438\ W

Explanation:

Given:

<u>the thermal resistance in the form of </u>

R_1=\frac{x_1}{k_1} =0.095\ m^2.^{\circ}C.W^{-1}

R_2=\frac{x_2}{k_2} =0.704\ m^2.^{\circ}C.W^{-1}

where:

x_1\  \&\ x_2 are the thickness of the respective bricks

k_1\ \&\ k_2 are the respective coefficient of conductivity

temperature inside the house, T_h=24\ ^{\circ}C

temperature outside the house, \ T_c=10^{\circ}C

area of the wall, A=20\ m^2

Since the bricks and insulation are used to construct a wall then they must be used in series for better shielding.

<u>Using Fourier's law:</u>

\dot Q=k.A.\frac{dT}{x}

\dot Q={dT}\div {\frac{x}{k.A} }

in series the resistances get add up

\dot Q=dT\div (\frac{x_1}{k_1.A}+\frac{x_2}{k_2.A} )

\dot Q=(24-10)\div (\frac{0.095 }{20}+ \frac{0.704 }{20} )

\dot Q=350.438\ W

7 0
2 years ago
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