A block rests on a flat plate that executes vertical simple harmonic motion with a period of 0.74 s. What is the maximum amplitu
1 answer:
Answer:
maximum amplitude = 0.13 m
Explanation:
Given that
Time period T= 0.74 s
acceleration of gravity g= 10 m/s²
We know that time period of simple harmonic motion given as
ω = 8.48 rad/s
ω=angular frequency
Lets take amplitude = A
The maximum acceleration given as
a= ω² A
The maximum acceleration should be equal to g ,then block does not separate
a= ω² A
10= 8.48² A
A=0.13 m
maximum amplitude = 0.13 m
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Explanation:
given data
density of current sheet = 0.40 A/m
length a = 0.27 m
width b = 0.63 m
For infinite sheet, magnetic field is given as
magnetic flux is given as
Answer with Explanation:
a.Intensity of radiation is directly proportional to the frequency of radiation
When the intensity of radiation increases then the frequency of radiation increases and therefore, the number of photo-electrons emitted by the metal increases.
b.When all of the wavelength in the radiation are increased by the same amount
We know that
Frequency is inversely proportional to the wavelength.
Therefore, the frequency decrease .
When the frequency decreases then the number of photo-electrons emitted by the metal decrease.
c.When the work function of the metal is increased then the gain of kinetic energy decreases .
When energy decreases then the number of photo-electrons emitted by the metal decreases.