1. I drop a penny from the top of the tower at the front of Fort Collins High School and it takes 1.85 seconds to hit the ground
1 answer:
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Answer:
468449163762.0812 W
Explanation:
m = Mass =
V = Volume =
r = Distance of sphere from isotropic point source of light = 0.5 m
R = Radius of sphere = 2 mm
= Density = 19 g/cm³
c = Speed of light =
A = Area =
I = Intensity =
g = Acceleration due to gravity = 9.81 m/s²
Force due to radiation is given by
According to the question
The power required of the light source is 468449163762.0812 W
The electrical potential energy of a charge q located at a point at potential V is given by
Therefore, if the charge must move between two points at potential V1 and V2, the difference in potential energy of the charge will be
In our problem, the electron (charge e) must travel across a potential difference V. So the energy it will lose traveling from the metal to the detector will be equal to
Therefore, if we want the electron to reach the detector, the minimum energy the electron must have is exactly equal to the energy it loses moving from the metal to the detector:
Therefore, if the charge must move between two points at potential V1 and V2, the difference in potential energy of the charge will be
In our problem, the electron (charge e) must travel across a potential difference V. So the energy it will lose traveling from the metal to the detector will be equal to
Therefore, if we want the electron to reach the detector, the minimum energy the electron must have is exactly equal to the energy it loses moving from the metal to the detector: