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Artemon [7]
2 years ago
10

A tourist bus is carrying passengers from the bottom of a hill to the top. The people, the bus, and the luggage can be analyzed

as a single machine structure system . The total amount of energy in the system decreases increases remains the same as the bus travels. This situation happens because some of the kinetic energy changes to kinetic potential thermal energy because of friction between the tires and the road.
Physics
2 answers:
ohaa [14]2 years ago
6 0

Answer:

A tourist bus is carrying passengers from the bottom of a hill to the top. The people, the bus, and the luggage can be analyzed as a single <em>system.</em> The total amount of energy in the system <em>decreases </em>as the bus travels. his situation happens because some of the kinetic energy changes to <em>thermal </em>energy because of friction between the tires and the road.

Explanation:

klasskru [66]2 years ago
4 0

Answer:

The total amount of energy in the system decreases as the bus travels. This situation happens because some of the kinetic energy changes to thermal energy because of friction between the tires and the road.

Explanation:

In an isolated system (= no external forces acting on it), the mechanical energy of the system remains constant:

E=U+K=const.

where U is the potential energy and K is the kinetic energy.

In this case, however, the system is not isolated. In fact, there is an external force acting on the bus: the force of friction. The force of friction acts against the motion of the bus, therefore the bus loses part of its energy, and its total energy decreases. This energy is converted into thermal energy (motion of the molecules of the surface of the road and of the wheel)  


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maxonik [38]

' W ' is the symbol for 'Watt' ... the unit of power equal to 1 joule/second.

That's all the physics we need to know to answer this question.
The rest is just arithmetic.

(60 joules/sec) · (30 days) · (8 hours/day) · (3600 sec/hour)

= (60 · 30 · 8 · 3600) (joule · day · hour · sec) / (sec · day · hour)

= 51,840,000 joules
__________________________________

Wait a minute !  Hold up !  Hee haw !  Whoa ! 
Excuse me.  That will never do.
I see they want the answer in units of kilowatt-hours (kWh).
In that case, it's

(60 watts) · (30 days) · (8 hours/day) · (1 kW/1,000 watts)

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= 14.4 kW·hour

Rounded to the nearest whole number:

14 kWh

7 0
2 years ago
flat block is pulled along a horizontal flat surface by a horizontal rope perpendicular to one of the sides. The block measures
Lelu [443]

Answer:

Answered

Explanation:

v= 1 m/s

A= 1 m^2

m= 100 kg

y= 1 mm

μ = ?

ζ= viscosity of  SAE 20 crankcase oil of 15° C= 0.3075 N sec/m^2

forces acting on the block are  

                                 F_s   ←    ↓     →F_f

                                                mg

N= mg

F_s=  shear force = ζAv/y        F_f= friction force = μN

now in x- direction F_s= F_f

ζAv/y  =  μN

0.3075×1×1×1/1×10^{-3} = μ×100

⇒μ=0.313 (coefficient of sliding friction for the block)

Now, as the velocity is increased shear force also increases and due to this frictional force also increases.

Now, to compensate this frictional force friction coefficient must increase

as v∝μ

7 0
2 years ago
Read 2 more answers
A 21200 kg sailboat experiences an eastward force 42700 N due to the tide pushing its hull while the wind pushes the sails with
My name is Ann [436]

Answer:

2.95 m/s^{2}

Explanation:

The resultant force F

F=\sqrt {F_{1}^{2}+F_{2}^{2}+2F_{1}F_{2}cos135^{o}} where F_{1} is eastward force, F_{2} is force directed towards the North

F=\sqrt {42700^{2}+85000^{2}+(2*42700*85000)cos135^{o}}=62573.17217 N

F=62573.2 N

The magnitude of acceleration of sailboat is given by

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7 0
2 years ago
A runner runs 300 m at an average speed of 3.0 m/s. She then runs another 300m at an average
Kaylis [27]

Answer:

B. 4 m/s

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v=d/t

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3 0
2 years ago
A 50-n crate sits on a horizontal floor where the coefficient of static friction between the crate and the floor is 0.50 . A 20-
andreyandreev [35.5K]

The resultant static friction force is equal to 20 N to the left.

Why?

I'm assuming that you forgot to write the question of the exercise, so,  I will try to complete it:

"A 50-n crate sits on a horizontal floor where the coefficient of static friction between the crate and the floor is 0.50 . A 20-n force is applied to the crate acting to the right. What is the resulting static friction force acting on the crate?"

So, if we are going to calculate the resulting static friction force, it means that there is no movement, we must remember that the friction coefficient will give us the maximum force before the crate starts to move.

We can calculate the static friction force by using the following formula:

Fr=F(appliedforce)

Since the crate is not moving (static), the static friction force acting on the crate will be equal to the applied force.

Calculating we have:

Fr=F(appliedforce)

Fr=20N

Hence, the static friction force is equal to 20 N to the left (since the applied force is acting to the right)

So,

FrictionForce=AppliedForce

Since the static friction force is equal to the applied force, the crate does not start to move.

Have a nice day!

8 0
2 years ago
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