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Alex
2 years ago
5

If the volume of a container of gas is reduced, what will happen to the pressure inside the container?

Chemistry
2 answers:
blondinia [14]2 years ago
8 0
B).The pressure will not change

andrew11 [14]2 years ago
5 0

Answer: a. The pressure will increase.

Explanation:

Boyle's Law: This law states that pressure is inversely proportional to the volume of the gas at constant temperature and number of moles.

P\propto \frac{1}{V}     (At constant temperature and number of moles)

{P_1V_1}={P_2V_2}

where,

P_1 = initial pressure of gas

P_2 = final pressure of gas

V_1 = initial volume of gas

V_2 = final volume of gas

Thus as volume of the container will be reduced, the pressure would increase.

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Zircon is a mineral with the empirical formula ZrSiO4. If all the zirconium is 90Zr, all the silicon is 28Si, and all the oxygen
Romashka-Z-Leto [24]

Answer:

3.52g

Explanation:

Zr = 90 g/mol

Si = 28 g/mol

O = 16 g/mol

ZrSiO4 = 90 + 28 + (16* 4) = 182g/mol

Mass =  Numberof moles * Molar mass

Mass = 1mol *  182g/mol = 182g

In one mole of ZrSiO4, there are 4 oxygen atoms, hence the mass is given as;

4 * 16 = 64g

Hence, 64g of oxygen is present in 182g of ZrSiO4.

10g would contain x

64 = 182

x = 10

x = ( 10 * 64 ) / 182

x = 640 / 182 = 3.52g

4 0
2 years ago
When 200g of AgNO3 solution mixes with 150 g of NaI solution, 2.93 g of AgI precipitates, and the temperature of the solution ri
gizmo_the_mogwai [7]

Answer:

\Delta H=1962.3J

Explanation:

Hello,

In this case, we can compute the change in the solution enthalpy by using the following formula:

\Delta H=mC\Delta T

Whereas the mass of the solution is 350 g, the specific heat capacity is 4.184 J/g °C and the change in the temperature is 1.34 °C, therefore, we obtain:

\Delta H=350g*4.184\frac{J}{g\°C} *1.34\°C\\\\\Delta H=1962.3J

It is important to notice that the mass is just 350 g that is the reacting amount and by means of the law of the conservation of mass, the total mass will remain constant, for that reason we compute the change in the enthalpy as shown above, which is positive due to the temperature raise.

Best regards.

8 0
2 years ago
How many structures are possible for a trigonal bipyramidal molecule with a formula of ax3y2?
ryzh [129]
Check the attached file for the answer.

4 0
2 years ago
Oxygen at 150 k and 41.64 atm has a tabulated specific volume of 4.684 cm3/g and a specific internal energy of 1706 j/mol. calcu
docker41 [41]

The total energy in a system due to the temperature and pressure per unit mass in that system is known as specific enthalpy. It is used in thermodynamic equations when one desires to know the energy for a given single unit mass of a component.  

Specific enthalpy is calculated by the equation:  

H = U + PV

in the given case, Specific volume = 4.684 cm³/g = 149.888 cm³/g moles = 149.888 × 10⁻³ J/g moles

Specific internal energy (U) is 1706 J/mol and pressure is 41.64.  

H = 1706 + 41.64 × 149.888 × 10⁻³ × 101.3 joules  

= 2428 joules / mole


5 0
2 years ago
What do you think happens to Difluoroethane at –24°C? Provide evidence to support your claim.
balandron [24]

Answer:

The following subsections explain the explanation according to the particular circumstance.

Explanation:

  • The boiling point seems to be the temperature beyond which the working fluid as well as the boiling phase would be at a predetermined pressure or voltage at equilibrium among one another and.  
  • The vapor or boiling temperature of 1,1 difluoroethane seems to be -25oC at 1 atm, although as a gas it can remain at a higher temperature around -24oC.
6 0
2 years ago
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