Saccharin, a sugar substitute, is a weak acid with pka=2.32 at 25 ∘c. it ionizes in aqueous solution as follows: hnc7h4so3(aq)←−
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Answer: 3
Explanation: This is a radioactive decay and all the radioactive process follows first order kinetics.
Equation for the reaction of decay of radioisotope follows:
By the stoichiometry of above reaction,
1 mole of is produced by 1 mole
So, 0.17 moles of will be produced by =
Amount of
decomposed will be = 0.17 moles
Initial amount of will be = Amount decomposed + Amount left = (0.17 + 0.024)moles =0.194 moles
where,
a = amount of reactant left after n-half lives = 0.024
= Initial amount of the reactant = 0.194
n = number of half lives= ?
Putting values in above equation, we get:
Therefore, 3 half lives have passed.