To solve this problem it is necessary to apply the concepts related to thermal stress. Said stress is defined as the amount of deformation caused by the change in temperature, based on the parameters of the coefficient of thermal expansion of the material, Young's module and the Area or area of the area.
Where
A = Cross-sectional Area
Y = Young's modulus
= Coefficient of linear expansion for steel
= Temperature Raise
Our values are given as,
Replacing we have,
Therefore the size of the force developing inside the steel rod when its temperature is raised by 37K is 38526.1N
Answer:
, 
Explanation:
The jet is flying at constant velocity: this means that its acceleration is zero, so the net force acting on the jet is also zero.
Therefore, we can write:
where
is the thrust force generated by each engine of the jet
is the drag force
Solving for Fd,
The velocity of the jet is
So, the rate at which the drag force does work (which is the power) is
and substituting
we find
Converting into horsepower,
The pressure needed in PSI = Pounds of force needed divided by the cylinder Area
The Cylinder rod Area is 21.19 sq inches
Thus, the pressure= 6800/21.19
= 320.91 PSI
Helium atom, in other words, it consistis of a particle having four protons and two neutrons.
Explanation:
The given data is as follows.
Mass of the ornament (
) = 0.9 kg
Length of the wire (l) = 1.5 m
Mass of missile (
) = 0.4 kg
Initial speed of missile (
) = 12 m/s
r = 1.5 m
According to the law of conservation of momentum,
Putting the given values into the above formula as follows.
0 + 4.8 = 1.3v
v = 3.69 m/s
Now, the centrifugal force produced is calculated as follows.
= 
= 11.80 N
Hence, tension in the wire is calculated as follows.
T = 
= 
= 24.54 N
Thus, we can conclude that tension in the wire immediately after the collision is 24.54 N.
