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anygoal [31]
2 years ago
10

The rate constant for a second-order reaction is 0.13 m-1 sec-1. if the initial concentration of reactant is 0.26 mol/l, it take

s __________ sec for the concentration to decrease to 0.13 mol/l.
Chemistry
1 answer:
kotykmax [81]2 years ago
5 0
The number  of seconds for  the concentration  to decrease  to  0.13 mol  for a second  order  reaction is  calculated  using  the below  formula

1/At  =-Kt  +1/Ao  where  At   is  the final concentration, Ao  is the   initial concentration.  t = time in second   while k =  constant

1/0.13 =-0.13 (t) + 1/0.26
like terms together

1/0.13-1/0.26 =-0.13 t
divide both side by 0.13

T =29.6 seconds


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In a particular mass of kau(cn)2, there are 6.66 × 1020 atoms of gold. What is the total number of atoms in this sample?
Vinvika [58]

Total number of atoms in the sample is the sum of number of atoms of all the elements present in the sample.

Number of gold, Au atoms in KAu(CN)_2 = 6.66\times 10^{20} atoms     (given)

From the formula of compound that is KAu(CN)_2 it is clear that the number of potassium and gold are same whereas those of carbon and nitrogen are 2 times of them.

So, the number of atoms of each element is:

Number of potassium, K atoms in KAu(CN)_2 = 6.66\times 10^{20} atoms    

Number of carbon, C atoms in KAu(CN)_2 = 2\times6.66\times 10^{20} atoms = 13.32\times 10^{20}

Number of nitrogen, N atoms in KAu(CN)_2 = 2\times6.66\times 10^{20} atoms = 13.32\times 10^{20}

Total number of atoms in KAu(CN)_2 = Number of gold, Au atoms+Number of potassium, K atoms +Number of carbon, C atoms + Number of nitrogen, N atoms

Total number of atoms in KAu(CN)_2 = 6.66\times 10^{20}+6.66\times 10^{20}+13.32\times 10^{20}+13.32\times 10^{20}

Total number of atoms in KAu(CN)_2 = 39.96\times 10^{20} atoms

Hence, the total number of atoms in KAu(CN)_2 is 3.996\times 10^{21} atoms.

7 0
2 years ago
In the formula X2O5, the symbol X could represent an element in Group
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Answer: (3) 15

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2 years ago
A radio technician measures the frequency of an AM radio transmitter. The frequency is 11979kHz. What is the frequency in megahe
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2 years ago
You can identify a metal by carefully determining its density. A 8.44 g piece of an unknown metal is 1.25 cm long, 2.50 cm wide,
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Thus density of the object will be 2.70 g/cm^3  which matches that of aluminium.

4 0
2 years ago
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