The angle whose sine is 0.39581 is

1 answer:

5 0

The angle whose sine is 0.39581 is 23.32 degrees. This is calculated by obtaining the arcsine of the value given above. The sine function is one of the basic functions in trigonometry together with cosine, tangent, cosecant,secant and cotangent.

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Your Turn

Elza [17]

Answer:

$y = 3x + 10$

$y = 3x + 15$

3 0

2 years ago

Hannah bought a total of 5.12 pounds of fruit at the market. She bought 2.5 pounds of pears and she also bought some bananas. Ho

lisov135 [29]

To find unknown part of a whole when there are two parts, subtract the part you do know from the whole. Subtract the lbs of pears from the total lbs. 5.12 lbs total - 2.5 lbs of pears = 2.62 lbs of bananas. 2.62 lbs of bananas is your answer.(my name is actually Hannah so I couldn't resist answering.)

5 0

2 years ago

Read 2 more answers

the members of the gardening group plan to build a walkway through the garden as formed by the IHOP potenuse of each of the four

aliya0001 [1]

Answer:

50.24 yards

Step-by-step explanation:

We will use the pythagorean theorem to find hypotenuse of each of the 4 triangles.

Pythagorean Theorem is $Hypotenuse^2=OneLeg^2+AnotherLeg^2$

For Spinach area, two of the legs are 8 and 6. Solving for hypotenuse:

$hyp^2=6^2+8^2\\hyp^2=100\\hyp=10$

For watermelon area, two of the legs are 12 and 8. Solving for hypotenuse:

$hyp^2=12^2+8^2\\hyp^2=208\\hyp=\sqrt{208}$

in red peppers area, the hypotenuse is already given as 15. But we need to find one leg since that will be the leg of the triangle in tomatoes area. Hypotenuse is 15 and one leg is 12, so the other leg is:

$15^2=12^2+eg^2\\15^2-12^2=leg^2\\leg=9$

So, in tomatoes area, we have one leg 9 and another leg 6. Solving for hypotenuse:

$hyp^2=9^2+6^2\\hyp^2=117\\hyp=\sqrt{117}$

Adding all the four hypotenuses, we get the length of the walkway:

Length of Walkway = $10+\sqrt{208} +15+\sqrt{117}\\ =50.24$ yards

8 0

2 years ago

Simplify 5 square root of 11 end root minus 12 square root of 11 end root minus 2 square root of 11. negative 33 square root of

Alla [95]

As long as your indexes are the same (which they are; they are all square roots) and you radicands are the same (which they are; they are all 11), then you can add or subtract. The rules for adding and subtracting radicals are more picky than multiplying or dividing. Just like adding fractions or combining like terms. Since all the square roots are the same we only have to worry about the numbers outside. In fact, it may help to factor out the sqrt 11: $(5-12-2) \sqrt{11}$ . The numbers subtract to give you -9. Therefore, the simplification is $-9 \sqrt{11}$