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Elenna [48]
1 year ago
5

A student heats a liquid on a burner. What happens to the portion of liquid that first begins to warm? What all applys

Physics
2 answers:
jeyben [28]1 year ago
5 0
For water, as the temperature goes up the density of the liquid water decreases therefore it becomes less dense so it tends to rise upward. And since the temperature here is higher, heat flows from the higher temperature to the lower so it releases energy to the environment. Therefore, the correct statements are 2, 3 and 5.
sineoko [7]1 year ago
5 0

Answer:

It becomes less dense.

It absorbs energy from the environment.

It rises upward.

Explanation:

Took the test!

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The space shuttle is descending through the earth's atmosphere. How is the force of gravity affected?
polet [3.4K]
The answer would be C. It will decrease with descent. Hope this helps!
5 0
2 years ago
Read 2 more answers
A 6.60-kg block slides with an initial speed of 1.56 m/s up a ramp inclined at an angle of 28.4° with the horizontal. The coeffi
Vlad [161]

Answer:

The distance travel by block before coming to rest is 0.122 m

Explanation:

Given:

Mass of block m = 6.60 kg

Initial speed of block v _{i} = 1.56 \frac{m}{s}

Final speed of block v_{f} = 0 \frac{m}{s}

Coefficient of kinetic friction \mu _{k} = 0.62

Ramp inclined at angle \theta = 28.4°

Using conservation of energy,

Work done by frictional force is equal to change in energy,

  \mu _{k} mgd \cos 28.4 =  \Delta K - \Delta U

Where \Delta U = mg d\sin 28.4

\mu _{k} mgd \cos 28.4 =  \frac{1}{2}mv_{i} ^{2} - mgd\sin 28.4

\mu _{k} mgd \cos 28.4 +mgd\sin 28.4  =  \frac{1}{2}mv_{i} ^{2}

d(6.60 \times 9.8 \times 0.62 \times 0.879 + 6.60 \times 9.8 \times 0.475) = \frac{1}{2} \times 6.60 \times (1.56)^{2}

 d = 0.122 m

Therefore, the distance travel by block before coming to rest is 0.122 m

7 0
2 years ago
A solid cylinder of mass 12.0 kg and radius 0.250 m is free to rotate without friction around its central axis. If you do 75.0 J
faltersainse [42]

Answer:

20 rad/s

Explanation:

mass, m = 12 kg

radius, r = 0.250 m

Moment of inertia of cylinder, I = 1/2 mr²

I = 0.5 x 12 x 0.250 x 0.250 = 0.375 kgm^2

Work done = Change in kinetic energy

Initial K = 0

Final K = 1/2 Iω²

W = 1/2 Iω²

ω² = 2W/ I = 2 x 75 / (0.375)

ω = 20 rad/s

Thus, the final angular velocity is 20 rad/s .

8 0
1 year ago
The maximum efficiency of a heat engine operating between 2 degrees c and 200 degrees c will be about:
Bess [88]
Hui4itfuwrtbitbwibrknfl3unfn6io4gnig4klg4mgmyy4m;l3
6 0
2 years ago
How does end A of the rod react when the charged ball approaches it after a great many previous contacts with end A? Assume that
sleet_krkn [62]

Answer: IT IS STRONGLY REPELLED

Explanation: The laws of guiding magnetic attraction or repulsion of Magnetic materials,states that when like poles are brought together they repel each other, but when unlike poles are brought together they are attracted.

The rod will be strongly repelled because the forces on the rod is greater and has the same Polarity as the charged ball.

6 0
1 year ago
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