Calculate the density, in g/L, of N2 gas at 35°C and 0.98 atm pressure.?
1 answer:
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Answer:
1. The pH of 1.0 M trimethyl ammonium (pH = 1.01) is lower than the pH of 0.1 M phenol (5.00).
2. The difference in pH values is 4.95.
Explanation:
1. The pH of a compound can be found using the following equation:
First, we need to find [H₃O⁺] for trimethyl ammonium and for phenol.
<u>Trimethyl ammonium</u>:
We can calculate [H₃O⁺] using the Ka as follows:
(CH₃)₃NH⁺ + H₂O → (CH₃)₃N + H₃O⁺
1.0 - x x x
By solving the above equation for x we have:
x = 0.097 = [H₃O⁺]
<u>Phenol</u>:
C₆H₅OH + H₂O → C₆H₅O⁻ + H₃O⁺
1.0 - x x x
Solving the above equation for x we have:
x = 9.96x10⁻⁶ = [H₃O⁺]
Hence, the pH of 1.0 M trimethyl ammonium is lower than the pH of 0.1 M phenol.
2. The difference in pH values for the two acids is:
Therefore, the difference in pH values is 4.95.
I hope it helps you!
Answer:
The K sp Value is
Explanation:
From the question we are told that
The of is = 122.5 g/ mol
The mass of dissolved is
The volume of solution is
The number of moles of is mathematically evaluated as
Substituting values
Generally concentration is mathematically represented as
For
The dissociation reaction of is
The solubility product constant is mathematically represented as
Since there is no ionic reactant we have