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2 years ago

What are three observations an astronaut might make while viewing Russia at night

Physics

1 answer:

Lunna [17]2 years ago

7 0

1. Physical size of Russia compared to other countries, despite a lack of visible borders from space.

2. Part of Russia's outline would likely be obscured by the various clouds and objects in the stratosphere; this would allow the astronaut to view potential cloud and weather patterns on earth.

3. An astronaut could see outlines of Russia's geography such as mountain ranges.

Hope that it helps :)

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Una columna de mármol, cuya área de sección transversal es de 2.0 m2 sostiene una masa de 25.000 kg. Encontrar: (3 pto )a) El es

bazaltina [42]

Responder:

122,500 Pa; 2.45 × 10 ^ -6; 2.94 × 10 ^ -5m

Explicación:

Dado lo siguiente:

Área de sección transversal (A) = 2m ^ 2

Masa (m) = 25000 kg

Módulo de Young = 50 x 10 ^ 9 N / m2

(1) estrés en la columna:

Estrés = Fuerza / Área

F = masa * aceleración debido a la gravedad

F = 25000kg * 9.8m / s ^ 2 = 245,000J

Estrés = 245,000J / 2m ^ 2

Estrés = 122,500 Pa

2) Deformación de la unidad (deformación):

Usando la relación:

Módulo de Young = Estrés / tensión

50 × 10 ^ 9 = 122,500 / CEPA

Cepa = 122500 / (50 × 10^9)

Cepa = 0.00000245

C) Si la altura es de 12 m, ¿cuánto se acorta la columna?

Cepa = extensión / longitud

0.00000245 = extensión / 12

0,00000245 * 12

0,0000294 m

7 0

2 years ago

If the Force exerted by the intern is doubled and the distance is halved, does the done by the intern increase, decrease, or rem

Jlenok [28]

Remain the same

Explanation:

If the force exerted by the intern is doubled and the distance is halved, the work done by the intern remains the same.

Work done is the force applied to move a body through a distance.

Work done = F x d

where F is the applied force

d is the distance moved

Now;

if:

f = 2f

d = $\frac{1}{2}$ d

Input the parameter:

Work done = fxd = 2f x $\frac{1}{2}$ d = fd

The work done will still remain the same

learn more:

Work done brainly.com/question/9100769

#learnwithBrainly

3 0

2 years ago

The statements below are all true. Some of them represent important reasons why the giant impact hypothesis for the Moon’s forma

Molodets [167]

Answer:

the order of importance must be b e a f c

Explanation:

Modern theories indicate that the moon was formed by the collision of a bad plant with the Earth during its initial cooling period, due to which part of the earth's material was volatilized and as a ring of remains that eventually consolidated in Moon.

Based on the aforementioned, let's analyze the statements in order of importance

b) True. Since the moon is material evaporated from Earth, its compassion is similar

e) True. If the moon is material volatilized from the earth it must train a finite receding speed

a) True. The solar system was full of small bodies in erratic orbits that wander between and with larger bodies

f) False. The moon's rotation and translation are equal has no relation to its formation phase

c) false. The amount of vaporized material on the moon is large

Therefore, the order of importance must be

b e a f c

5 0

2 years ago

In the winter sport of bobsledding, athletes push their sled along a horizontal ice surface and then hop on the sled as it start

Hitman42 [59]

Answer:

$v_f = 16.6 m/s$

Explanation:

As we know by force equation that force along the inclined planed due to gravity is given as

$F_g = mg sin\theta$

so the acceleration due to gravity along the plane is given as

$a = \frac{F_g}{m}$

now we have

$a = g sin\theta$

$a = (9.81 sin4.0)$

$a = 0.68 m/s^2$

now we know that

$v_f^2 - v_i^2 = 2 a d$

$v_f^2 - 9.2^2 = 2(0.68)(140)$

$v_f = 16.6 m/s$

4 0

2 years ago

How many top quark lifetimes have there been in the history of the universe (i.e., what is the age of the universe divided by th

ololo11 [35]

Answer:

$1.0\cdot 10^{41}$ times

Explanation:

First of all, we need to write both the age of the universe and the lifetime of the top quark in scientific notation.

Age of the universe:

$T=100,000,000,000,000,000s = 1.0\cdot 10^{17} s$ (1 followed by 17 zeroes)

Lifetime of the top quark:

$\tau = 0.000000000000000000000001s = 1.0\cdot 10^{-24} s$ (we moved the decimal point 24 places to the right)

Therefore, to answer the question, we have to calculate the ratio between the age of the universe and the lifetime of the top quark:

$r = \frac{T}{\tau}=\frac{1.0\cdot 10^{17} s}{1.0\cdot 10^{-24} s}=1.0\cdot 10^{41}$

6 0

2 years ago