The minimum potential difference must be supplied by the ignition circuit to start a car is -1800 V
<u>Explanation:</u>
Given data,
E= 3 ×10 ⁶ Δx=0.06/100
We have to find the minimum potential difference
E= -ΔV/Δx
ΔV=- E × Δx
ΔV =-3 ×10 ⁶ . 0.06/100
ΔV=-1800 V
The minimum potential difference must be supplied by the ignition circuit to start a car is -1800 V
Answer:
(a) 160000 kV/m
(b) 1336 keV
Explanation:
(a) magnetic filed, B = 10 T
energy of electron, E = 740 eV
mass of electron, m = 9.1 x 10^-31 kg
Let v be the velocity of electron.
E = 1/2 mv^2
740 x 1.6 x 10^-19 = 0.5 x 9.1 x 10^-31 x v^2
v = 1.6 x 10^7 m/s
v = E / B
E = v x B = 1.6 x 10^7 x 10 = 16 x 10^7 V/m
E = 160000 kV/m
(b) E = 16 x 10^7 V/m
B = 10 T
Let v be the velocity of protons.
v = E / B = 16 x 10^7 / 10 = 1.6 x 10^7 m/s
Kinetic energy of proton, E = 1/2 mv^2
= 0.5 x 1.67 x 10^-27 x 1.6 x 1.6 x 10^14
= 2.14 x 10^-13 J = 1336000 eV = 1336 keV
The question is missing, but I guess the problem is asking for the distance between the cliff and the source of the sound.
First of all, we need to calculate the speed of sound at temperature of

:

The sound wave travels from the original point to the cliff and then back again to the original point in a total time of t=4.60 s. If we call L the distance between the source of the sound wave and the cliff, we can write (since the wave moves by uniform motion):

where v is the speed of the wave, 2L is the total distance covered by the wave and t is the time. Re-arranging the formula, we can calculate L, the distance between the source of the sound and the cliff: