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2 years ago

Draw the missing constitutional isomer that has molecular formula c5h10 and contains one ring.

Chemistry

1 answer:

ikadub [295]2 years ago

4 0

There can be following constitutional isomers of a compound with molecular formula C5H10

Constitutional isomers are those compounds which differ in structure due to difference in bonding and position of atoms

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What is the total amount of heat required to completely melt 347 grams of ice at its melting point

jolli1 [7]

In order to calculate the amount of heat energy required to melt 347 grams of ice, we need to will apply the equation:
Q = ml, where m is the mass of substance and l is its latent heat of fusion. For ice, the latent heat of fusion is 334 joules per gram. Therefore:
Q = 347 x 334
Q = 112,558 joules of energy

8 0

2 years ago

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What is the total pressure of air in lungs of an individual with oxygen at 100. mmHg, nitrogen at 573 mmHg, carbon dioxide at 0.

ryzh [129]

Answer: The total pressure of air in lungs of an individual is 760.28 mm Hg

Explanation:

According to Dalton's law, the total pressure is the sum of individual pressures.

$p_{total}=p_A+p_B+p_C...$

Given : $p_{total}$ =total pressure of gases = ?

$p_{O_2}$ = partial pressure of oxygen = 100 mm Hg

$p_{N_2}$ = partial pressure of nitrogen = 573 mm Hg

$p_{CO_2}$ = partial pressure of Carbon dioxide = 0.053 atm = 40.28 mm Hg(1 atm = 760 mmHg)

$p_{H_2O}$ = partial pressure of water vapor = 47 torr = 47 mm Hg (1torr=1 mm Hg)

putting in the values we get:

$p_{total}=(100+573+40.28+47)mmHg$

$p_{total}=760.28mmHg$

Thus the total pressure of air in lungs of an individual is 760.28 mm Hg

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2 years ago

Analyze and solve this partially completed galvanic cell puzzle. There are 4 electrodes each identified by a letter of the alpha

klasskru [66]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The correct option is $E_{cell}__{AC}} = 0.94$

Explanation:

From the question we are told that

the cell voltage for AD is $E_{cell}__{AD}} = 1.56V$

From the data give we can see that

$E_{cell}__{AD}} - E_{cell}__{BD}} = E_{cell}__{AB}}$

i.e $1.56 - 1.53 = 0.03$

In the same way we can say that

$E_{cell}__{AD}}-E_{cell}__{CD}} = E_{cell}__{AC}}$

=> $E_{cell}__{AC}}=1.56- 0.62$

$E_{cell}__{AC}} = 0.94$

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2 years ago

Describe how you would prepare approximately 2 l of 0.050 0 m boric acid, b(oh)3.

Elenna [48]

The given concentration of boric acid = 0.0500 M

Required volume of the solution = 2 L

Molarity is the moles of solute present per liter solution. So 0.0500 M boric acid has 0.0500 mol boric acid present in 1 L solution.

Calculating the moles of 0.0500 M boric acid present in 2 L solution:

$2 L * \frac{0.0500 mol B(OH)_{3} }{1 L} = 0.100 mol B(OH)_{3}$

Converting moles of boric acid to mass:

$0.100 mol B(OH)_{3} * \frac{61.83 g}{mol B(OH)_{3}} = 6.183 g$

Therefore, 6.183 g boric acid when dissolved and made up to 2 L with distilled water gives 0.0500 M solution.

5 0

2 years ago

A sample of an unknown compound with a mass of 0.847 g has the following composition: 50.51 % fluorine and 49.49 % iron. When th

sergejj [24]

Answer: 0,4278g of F and 0,4191g of Fe

Explanation: it's possible to calculate the mass of each element by multiplying the percentage (decimal) of the element by the mass of the compound.

For Fluorine (F)

0,847g * 0,5051 = 0,4278g of F

For iron (Fe)

0,847 * 0,4949 = 0,4191g of Fe

This is determined because even when the compound is decomposed, due to conservative law of mass, the decomposition process do not affect the amount of matter, so the mass of the elements remain even if they are separated from the original molecule.

At the end, the sum of the elements masses should be the total mass of the compound.

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2 years ago

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