Answer:
The value is 
Explanation:
From the we are told that
The radius of the sphere is 
The temperature is 
The average temperature of the rest of the universe is 
Generally the change in entropy of the entire universe per second is mathematically represented as
Here 
is the entropy of the rest of the universe which is mathematically represented as
Here Q is the quantity of heat radiated by the star which is mathematically represented as
Here 
is the Stefan-Boltzmann constant with value
=> 
=> 
So
=> 
Here 
is the entropy of the rest of the universe which is mathematically represented as
=> 
=> 
So
=>
Answer:
v_average = 500 m / min
Explanation:
Average speed is defined
v = (x_{f} -x₀) / Δt
let's look in each section
section 1
the variation of the distance is 800 in a time of 1.4 min
v₁ = 800 / 1.4
v₁ = 571.4 m / min
section 2
distance interval 500 in a 1.6 min time interval
v₂ = 500 / 1.6
v₂ = 312.5 m / min
section 3
distance interval 1200 m in a time 2 min
v₃ = 1200/2
v₃ = 600 m / min
taking the speed of each section we can calculate the average speed
the distance traveled
Δx = 800 + 500 + 1200
Δx = 2500 m
the time spent
Δt = 1.4 + 1.6+ 2
Δt = 5 min
v_average = Δx / Δt
v_average = 2500/5
v_average = 500 m / min
Answer:
towards left
Explanation:
As we know that there is no external force on the system of two cart so total momentum of the system is conserved
so we will say
now plug in all data into the above equation
here we assumed that left direction of motion is negative while right direction is positive
so we can solve it for speed v now
Answer:
(a) 29 cm
(b) 43.5 cm
Explanation:
(a) when loop A is slack, there are three forces acting on the metre rule.
-0.9 N at 50 cm mark
T at 70 cm mark
-2 N at x
Taking the sum of the torques about B:
∑τ = Iα
(-0.9 N) (50 cm − 70 cm) + (-2 N) (x − 70 cm) = 0
18 Ncm − 2 N (x − 70 cm) = 0
2 N (x − 70 cm) = 18 Ncm
x − 70 cm = 9 cm
x = 79 cm
The distance from the center is |50 cm − 79 cm| = 29 cm.
(b) when loop B is slack, there are three forces acting on the metre rule.
-0.9 N at 50 cm mark
T at 20 cm mark
-2 N at x
Taking the sum of the torques about A:
∑τ = Iα
(-0.9 N) (50 cm − 20 cm) + (-2 N) (x − 20 cm) = 0
-27 Ncm − 2 N (x − 20 cm) = 0
2 N (x − 20 cm) = -27 Ncm
x − 20 cm = -13.5 cm
x = 6.5 cm
The distance from the center is |50 cm − 6.5 cm| = 43.5 cm
Moon diameter - 2,160 miles Sun diameter - 864,000 miles
So, in terms of diameter the Sun is 400 times bigger then the Moon. If we divide 150,000,000 km by 384,000 km we get 390.625 almost the same number.
The Sun and the Moon have sizes which vary a small amount as seen from Earth.
The Sun appears largest about January 4th and smallest around July 4th.
