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Savatey [412]
2 years ago
9

Energy can be changed from one form to another. Which terms can be used to describe these changes? Check all that apply.

Physics
2 answers:
OverLord2011 [107]2 years ago
6 0

Answer:

A.) Energy Conversion

D.) Energy Transformation

[ Correct on Edgenuity ]

Explanation:

These other listed options are incorrect because :

(bolded sentences are the reason why)

Incorrect : B.) Energy conservation  

Energy conservation is the <u>prevention</u> of the wasteful use of energy, especially in order to ensure its continuing availability. This does not describe change; it talks about prevention.

Incorrect : C.) Energy correlation

The energy correlation is a <u>measure</u> of how much the <u>movement</u> of one electron is influenced by the presence of all other electrons. This only describes the measure of movement and not the physical form of energy change.

Incorrect : E.) Energy transference

Energy transference is the <u>conversion</u> of one form of energy into another, or the movement of energy from one place to another. It has the correct definition but this is the incorrect term that's being used. Instead, you would have used energy transformation.

*[ A and B are correct, I recieved 100% on the quiz on Edgenuity ]*

Hope this helped! Have a wonderful day! :)

Dominik [7]2 years ago
4 0

Answer:

A Energy Conversion

B Energy Conservation

D Energy Transformation

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980 kJ

Explanation:

Work = change in energy

W = mgh

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W = 980 kJ

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2 years ago
An astronaut weighs 8.00 × 102 newtons on the sur- face of Earth. What is the weight of the astronaut 6.37 × 106 meters above th
kolbaska11 [484]

Answer:

mg=200.4 N.

Explanation:

This problem can be solved using Newton's law of universal gravitation: F=G\frac{m_{1}m_{2}}{r^{2}},

where F is the gravitational force between two masses m_{1} and m_{2}, r is the distance between the masses (their center of mass), and G=6.674*10^{-11}(m^{3}kg^{-1}s^{-2}) is the gravitational constant.

We know the weight of the astronout on the surface, with this we can find his mass. Letting w_{s} be the weight on the surface:

w_{s}=mg,

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m=(8*10^{2})/g,

since we now that g=9.8m/s^{2} we get that the mass is

m=81.6kg.

Now we can use Newton's law of universal gravitation

F=G\frac{Mm}{r^{2}},  

where m is the mass of the astronaut and M is the mass of the earth. From Newton's second law we know that

F=ma,

in this case the acceleration is the gravity so

F=mg, (<u>becarefull, gravity at this point is no longer</u> 9.8m/s^{2} <u>because we are not in the surface anymore</u>)

and this get us to

mg=G\frac{Mm}{r^{2}}, where mg is his new weight.

We need to remember that the mass of the earth is M=5.972*10^{24}kg and its radius is 6.37*10^{6}m.

The total distance between the astronaut and the earth is

r=(6.37*10^{6}+6.37*10^{6})=2(6.37*10^{6})=12.74*10^{6} meters.

Now we can compute his weigh:

mg=G\frac{Mm}{r^{2}},

mg=(6.674*10^{-11})\frac{(5.972*10^{24})(81.6)}{(12.74*10^{6})^{2}},

mg=200.4 N.

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Explanation:

since P=W/t

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