Answer:
The Michaelis‑Menten equation is given as
v₀ = Kcat X [E₀] X [S] / (Km + [S])
where,
Kcat is the experimental rate constant of the reaction; [s] is the substrate concentration and
Km is the Michaelis‑Menten constant.
Explanation:
See attached image for a detailed explanation
The answer:
<span>The equation of its dissolution in water is: AgNO3 → Ag + (aq) + NO3- (aq)
and </span>AgNO3 → Ag + (aq) + NO3- (aq)
1 mol 1mol 1mol
? -------- 0.854mo
so for finding the value, it is sufficients to complute 1 x 0.854 mol =0.854 mol
so, 0.854 mol is required for the reaction to form 0.854 mol of Ag
<span>0.127 moles
The formula for nitroglycerin is C3H5N3O9 so let's first calculate the molar mass of it.
Carbon = 12.0107
Nitrogen = 14.0067
Hydrogen = 1.00794
Oxygen = 15.999
C3H5N3O9 = 3 * 12.0107 + 5 * 1.00794 + 3 * 14.0067 + 9 * 15.999 = 227.0829
Now calculate the number of moles of nitroglycerin you have by dividing the mass by the molar mass
2.50 ml * 1.592 g/ml / 227.0829 g/mol = 0.017527 mol
The balanced formula for when nitroglycerin explodes is
4 C3H5N3O9 => 12 CO2 + 10 H2O + O2 + 6 N2
Since all of the products are gasses at the time of the explosion, there is a total of 29 moles of gas produced for every 4 moles of nitroglycerin
Now multiply the number of moles of nitroglycerin by 29/4
0.017527 mol * 29/4 = 0.12707075 moles
Round to 3 significant figures, giving 0.127 moles</span>
A) 5.2 x 10^2
B) 86.
C) 6.4 x 10^3
D) 5.0
E) 22.
F) 0.89
