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2 years ago

If a 1,300 kg car with no people inside is on the edge of a cliff 1,500 m above the ground, what is its potential energy?

Physics

1 answer:

Ghella [55]2 years ago

3 0

Given that

mass (m) = 1300 Kg ,

height (h) = 1500 m

Determine the potential energy ?

P.E = m × g × h

= 1300 × 9.81 × 1500

= 19129500 Joules

= 19129.5 KJ

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Jet001 [13]

Answer: Change in ball's momentum is 1.5 kg-m/s.

Explanation: It is given that,

Mass of the ball, m = 0.15 kg

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1 year ago

The angle θ is slowly increased. Write an expression for the angle at which the block begins to move in terms of μs.

Reika [66]

Answer:

$tan \theta = \mu_s$

Explanation:

An object is at rest along a slope if the net force acting on it is zero. The equation of the forces along the direction parallel to the slope is:

$mg sin \theta - \mu_s R =0$ (1)

where

$mg sin \theta$ is the component of the weight parallel to the slope, with m being the mass of the object, g the acceleration of gravity, $\theta$ the angle of the slope

$\mu_s R$ is the frictional force, with $\mu_s$ being the coefficient of friction and R the normal reaction of the incline

The equation of the forces along the direction perpendicular to the slope is

$R-mg cos \theta = 0$

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Solving for R,

$R=mg cos \theta$

And substituting into (1)

$mg sin \theta - \mu_s mg cos \theta = 0$

Re-arranging the equation,

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This the condition at which the equilibrium holds: when the tangent of the angle becomes larger than the value of $\mu_s$ , the force of friction is no longer able to balance the component of the weight parallel to the slope, and so the object starts sliding down.

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2 years ago

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lisabon 2012 [21]

As per kinematics equation we are given that

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now we need to find x

from above equation we have

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$x = 93.2 m$

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2 years ago

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satela [25.4K]

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gayaneshka [121]

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2 years ago

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