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alisha [4.7K]
2 years ago
9

A group of marine scientists introduced a species of fish into an artificial habitat and wanted to determine whether it will gro

w well in the new environment. They recorded the population over several years and their data is plotted below. Analyze the data and formulate a conclusion. Does this species of fish do well in this habitat? Predict what will happen to the population over the next five years.

Physics
2 answers:
krek1111 [17]2 years ago
6 0

Enumerating the data points from the chart over ten years:

{100, 105, 95, 102, 93, 105, 98, 99, 101, 100}

Their initial, final, and the median values are all 100. The mean value is 99.8, and the standard deviation slightly less than 3.9. All of these statistics indicate stability of the population over the observed span of ten years. There is neither a significant growth, nor a decline. Assuming stability is what corresponds to a species doing well in a habitat, a conclusion can be made that the species is doing well!

Provided the conditions of the artificial habitat won't change significantly  in the next five years, the population will continue to remain close to an average of 100, with minor deviations of +/- 4 likely year by year.

valina [46]2 years ago
6 0

the population at year ends was 100, 105, 95, 102,93, 105,98,102 and 100. mean is 100. so the fish population is not growing or declining after 9 years. it means the fish is doing ok; not well enough to increase its pop'n but not bad to decrease either.


over the  next 5 yrs, pop'n likely to stay around 100.


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Rasek [7]

Answer:

t = 4.17 [s]

Explanation:

We know that work is defined as the product of force by distance.

W = F*d

where:

F = force [N] (units of Newtons)

d = distance = 6.34 x 10⁴ [mm] = 63.4 [m]

In order to find the force, we must determine the weight of the box, the weight can be determined by means of the product of mass by gravitational acceleration.

w = m*g

where:

m = mass = 1.47 x 10⁴ [g] = 14.7 [kg]

g = gravity acceleration = 9.81 [m/s²]

w = 14.7*9.81

w = 144.2 [N]

Therefore the work can be calculated.

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W = 144.2*63.4

W = 9142.72 [J] (units of Joules)

Power is now defined in physics as the relationship of work at a given time

P = W/t

where:

P = power = 2190 [W]

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Now clearing t, we have.

t = W/P

t = 9142.72/2190

t = 4.17 [s]

6 0
1 year ago
A thin, horizontal, 18-cm-diameter copper plate is charged to -3.8 nC. Assume that the electrons are uniformly distributed on th
son4ous [18]

Answer:

Part a)

E = 8436.7 N/C

Part b)

E = 8436.7 N/C

Explanation:

Part a)

Electric field due to large sheet is given as

E = \frac{\sigma}{2\epsilon_0}

\sigma = \frac{Q}{A}

Q = -3.8 nC

A = \pi(0.09)^2

A = 0.025 m^2

\sigma = \frac{-3.8\times 10^{-9}}{0.025}

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now the electric field is given as

E = \frac{-1.5 \times 10^{-7}}{2(8.85 \times 10^{-12})}

E = 8436.7 N/C

Part b)

Now since the electric field is required at same distance on other side

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E = 8436.7 N/C

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2 years ago
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Lelechka [254]

Answer:

7.894 Hours.

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Based on information number hours that this battery will last with give load  has mathematical relation of.

t = \frac{60Ah}{load in amperes.}

with load 60A t =  1h, 30A t = 2h so on and forth.

two head lights draw total current of 2x3.8A = 7.6A.

putting this in above relation gives.

t = \frac{60Ah}{7.6A}=7.894 h.

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2 years ago
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snow_lady [41]

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Now the relationship between wavelength \lambda, frequency f and speed v of the waves is:

v=\lambda f

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\boxed{v=0.06*4.922=0.296m/s}

Now the period T is just the inverse of the frequency, or

T=\frac{1}{f}

\boxed{T=\frac{1}{4.933}=0.203\:seconds }

4 0
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As we know by the formula of bulk modulus

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5 0
2 years ago
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