24 minus 8 is 16
5 times 60 is 300
300 times 16 is 4800.
She winks 4800 times a day
Let's look at the molar weight of the answers:
NO is 30 g/mol
NO2 is 46
N2O is 44
N2O4 is 124
<span>We have the grams of the product, so we need the moles in order to calculate the molar weight. We us PV=nRT for this, assuming standard temperature and pressure. </span>
You were given the liters (.120L)
Std pressure is 1 atmosphere
You're looking for n, the number of moles
<span>Temp is 293.15 kelvin, thats standard </span>
And r is the gas constant in liters-atm per mol kelvin
(.120 liters)(1atm)=n(293.15K)(.08206)
Solving for n is .0049883835 mol
<span>.23g divided by .0049883 mol is about 46g/mol. You're answer is B I think, NO2
I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
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Answer:

Explanation:
Hello!
In this case, since the dissolution of copper (I) chloride is:

And its equilibrium expression is:
![Ksp=[Cu^+][Cl^-]](https://tex.z-dn.net/?f=Ksp%3D%5BCu%5E%2B%5D%5BCl%5E-%5D)
We can represent the molar solubility via the reaction extent as
, however, since there is 0.050 M KCl we immediately add such amount to the chloride ion concentration since KCl is readily ionized; therefore we write:

Thus, solving for
, we obtain:

By using the quadratic equation, we obtain:

Clearly, the solution is
because no negative results are
allowed. Therefore, the molar solubility is:

Best regards!
Answer: The stick model method
Answer:
a. The atom will go from a two-dimensional configuration to a three dimensional configuration.
d. The bond angle will increase.
f. The number of unhybridized p orbitals will decrease.
Explanation:
Sp2 is the atomic bond in which orbitals mixes with only two orbitals. These orbitals form three sp2. When two carbon atoms are overlapped they form sigma bond by overlapping of sp2 bonds. Sp3 bond is created when there is one lone molecule available for combination. When the bonding is updated from sp2 to sp3 then unhybridized orbitals will decrease causing the bond angle to increase.