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Bad White [126]
2 years ago
12

At 1.01 bar, how many moles of CO2 are released by raising the temperature of 1 litre of water from 20∘C to 25∘C

Chemistry
1 answer:
Tatiana [17]2 years ago
5 0

Answer: 0.0007 moles of CO_2 is released when temperature is raised.

Explanation:

To calculate the number of moles, we use the ideal gas equation, which is:

PV=nRT

where,

P = pressure of the gas = 1.01 bar

V = Volume of the gas = 1L

R = Gas constant = 0.08314\text{ L bar }mol^{-1}K^{-1}

  • Number of moles when T = 20° C

Temperature of the gas = 20° C = (273 + 20)K = 293K

Putting values in above equation, we get:

1.01bar\times 1L=n_1\times 0.0814\text{ L bar }mol^{-1}K^{-1}\times 293K\\n_1=0.04146moles

  • Number of moles when T = 25° C

Temperature of the gas = 25° C = (273 + 25)K = 298K

Putting values in above equation, we get:

1.01bar\times 1L=n_2\times 0.0814\text{ L bar }mol^{-1}K^{-1}\times 298K\\n_2=0.04076moles

  • Number of moles released = n_1-n_2=0.04146-0.04076=0.0007moles

Hence,  0.0007 moles of CO_2 is released when temperature is raised from 20° C to 25° C

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<span>We have the grams of the product, so we need the moles in order to calculate the molar weight. We us PV=nRT for this, assuming standard temperature and pressure. </span>
You were given the liters (.120L) 
Std pressure is 1 atmosphere 
You&#x27;re looking for n, the number of moles 
<span>Temp is 293.15 kelvin, thats standard </span>
And r is the gas constant in liters-atm per mol kelvin 

(.120 liters)(1atm)=n(293.15K)(.08206) 
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<span>.23g divided by .0049883 mol is about 46g&#x2F;mol. You&#x27;re answer is B I think, NO2

I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
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4 0
2 years ago
Read 2 more answers
Determine the molar solubility of CuCl in a solution containing 0.050 KCl. Ksp of CuCl is 1.0 x 10-6
Volgvan

Answer:

2.0x10^{-5}\frac{mol}{L}

Explanation:

Hello!

In this case, since the dissolution of copper (I) chloride is:

CuCl(s)\rightarrow Cu^++Cl^-

And its equilibrium expression is:

Ksp=[Cu^+][Cl^-]

We can represent the molar solubility via the reaction extent as x, however, since there is 0.050 M KCl we immediately add such amount to the chloride ion concentration since KCl is readily ionized; therefore we write:

1.0x10^{-6}=(x)(0.050+x)

Thus, solving for x, we obtain:

1.0x10^{-6}=0.050x+x^2\\\\x^2+0.050x-1x10^{-6}=0

By using the quadratic equation, we obtain:

x_1=2.0x10^{-5}M\\\\x_2=-0.05M

Clearly, the solution is x_1=2.0x10^{-5}M because no negative results are

allowed. Therefore, the molar solubility is:

2.0x10^{-5}\frac{mol}{L}

Best regards!

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Select all true statements about hybridization, of a second-row element, changing from sp2 to sp3. (max of 3 choices) a. The ato
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Answer:

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d. The bond angle will increase.

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Explanation:

Sp2 is the atomic bond in which orbitals mixes with only two orbitals. These orbitals form three sp2. When two carbon atoms are overlapped they form sigma bond by overlapping of sp2 bonds. Sp3 bond is created when there is one lone molecule available for combination. When the bonding is updated from sp2 to sp3 then unhybridized orbitals will decrease causing the bond angle to increase.

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