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2 years ago

Which term do modern psychologists prefer to use in place of short-term memory?

Physics

1 answer:

Vsevolod [243]2 years ago

7 0

Correct answer: D). Working Memory

The short term memory is the part of the memory system in which the information is stored for 30 seconds. However, it can be increased by rehearsal. Short term memory is also called active memory or the working memory. The working memory is the part of the cognitive system that is responsible for storing information temporarily for processing. It is important for reasoning.

Hence, the correct answer would be option D.

You might be interested in

would an elephant standing on one leg exert a higher force on a scale than an elephant on four legs. why

zlopas [31]

Answer:

no becaus force is mass multiplied by acceleration. the mass of the elephant does not change

7 0

2 years ago

A metal disk weighing 1 N is resting on an index card that is balanced on top of a glass. When the index card is quickly pulled

Burka [1]

Answer: D

Step by step explanation:

8 0

2 years ago

Read 2 more answers

A block spring system oscillates on a frictionless surface with an amplitude of 10\text{ cm}10 cm and has an energy of 2.5 \text

antoniya [11.8K]

Answer:

The energy of the system is 15 J.

Explanation:

Given that,

Energy E = 2.5 J

Amplitude = 10 cm

We need to calculate the spring constant

Using formula of mechanical energy of the system

$E=\dfrac{1}{2}kA^2$

Put the value into the formula

$2.5=\dfrac{1}{2}k\times(10\times10^{-2})^2$

$k=\dfrac{2.5\times2}{(10\times10^{-2})^2}$

$k=500\ N/m$

If the block is replaced by a block with twice the mass of the original block

Amplitude = 6 cm

We need to calculate the energy

Using formula of mechanical energy

$E=\dfrac{1}{2}kA^2$

Put the value into the formula

$E=\dfrac{1}{2}\times500\times(6\times10^{-2})$

$E=15\ J$

Hence, The energy of the system is 15 J.

8 0

2 years ago

When two objects are in contact, moving together, which of the following statements must be true? Choose all that apply. When tw

Setler [38]

Answer:

The objects must have the same acceleration and the objects must exert the same magnitude force on each other.

Explanation:

The objects must have the same weight: FALSE. This is not needed, any two object can move together in contact no matter their mass.

The objects must have the same acceleration: TRUE. If they have different accelerations, they will separate since the distance each of them travel at a given time will be different.

The objects must have the same net force acting on them: FALSE. This is not needed, since what matters is acceleration, and a=F/m, so if both objects have different net force acting on them, they could have different masses also to compensate and result in the same acceleration.

The objects must exert the same magnitude force on each other: TRUE, this is the 3rd Newton Law, an action must follow the same reaction.

7 0

2 years ago

The mass m1 enters from the left with velocity v0 and strikes a mass m2 > m1 which is initially at rest. The collision betwee

enot [183]

Answer:

1. False 2) greater than. 3) less than 4) less than

Explanation:

As the collision is perfectly elastic, kinetic energy must be conserved.
The expression for the final velocity of the mass m₁, for a perfectly elastic collision, is as follows:

$v_{1f} = v_{10} *\frac{m_{1} -m_{2} }{m_{1} +m_{2}}$

As it can be seen, as m₁ ≠ m₂, v₁f ≠ 0.

As total momentum must be conserved, we can see that as m₂ > m₁, from the equation above the final momentum of m₁ has an opposite sign to the initial one, so the momentum of m₂ must be greater than the initial momentum of m₁, to keep both sides of the equation balanced.

The maximum energy stored in the in the spring is given by the following expression:

$U =\frac{1}{2} *k * A^{2}$

where A = maximum compression of the spring.

This energy is always the sum of the elastic potential energy and the kinetic energy of the mass (in absence of friction).
When the spring is in a relaxed state, the speed of the mass is maximum, so, its kinetic energy is maximum too.
Just prior to compress the spring, this kinetic energy is the kinetic energy of m₂, immediately after the collision.
As total kinetic energy must be conserved, the following condition must be met:

$KE_{10} = KE_{1f} + KE_{2f}$

So, it is clear that KE₂f < KE₁₀
Therefore, the maximum energy stored in the spring is less than the initial energy in m₁.

As explained above, if total kinetic energy must be conserved:

$KE_{10} = KE_{1f} + KE_{2f}$

So as kinetic energy is always positive, KEf₂ < KE₁₀.

4 0

2 years ago