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2 years ago

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A gas at constant volume has a pressure of 2.80 atm at 400. K. What will be the pressure of the gas at 360. K?

1 answer:

madreJ [45]2 years ago

3 0

Hello!

A gas at constant volume has a pressure of 2.80 atm at 400. K. What will be the pressure of the gas at 360. K?

We have the following information:

P1 (initial pressure) = 2.80 atm

T1 (initial temperature) = 400 K

P2 (final pressure) = ? (in atm)

T2 (final temperature) = 360 K

According to the Law of Charles and Gay-Lussac in the study of gases, we have an isochoric (or isovolumetric) transformation when its volume remains constant or equal, if the temperature increases, the pressure increases and, if the temperature decreases, the pressure also decreases, they are directly proportional.then we will have the following formula:

$\dfrac{P_1}{T_1} = \dfrac{P_2}{T_2}$

$\dfrac{2.80}{400} = \dfrac{P_2}{360}$

multiply the means by the extremes

$400*P_2 = 2.80*360$

$400\:P_2 = 1008$

$P_2 = \dfrac{1008}{400}$

$\boxed{\boxed{P_2 = 2.52\:atm}}\end{array}}\qquad\checkmark$

Answer:

2.52 atm

_______________________________

I Hope this helps, greetings ... Dexteright02! =)

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