answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
harina [27]
2 years ago
4

A device having a constant resistance operates at a voltage of 100 V. If the voltage supplied to the device increases by 10 perc

ent, how does this affect the power used by the device relative to the power consumption at 100 V?
Physics
1 answer:
zysi [14]2 years ago
8 0

P=V^2/R

In the first case voltage is 100V, in the second case it is 110V

P1=10000/R

P2=12100/R

R=P1/10000

R=P2/12100

P1/10000=P2/12100

12100 . P1=P2 . 10000

Divide both by 100

P1 . 121=P2 . 100

Therefore Power in the second scenario is 21% less than the first one

You might be interested in
A point charge Q = -400 nC and two unknown point charges, q1 and q2, are placed as shown. Point charge q1 is located 1.3 meters
nalin [4]
120 nC is the answer




Sorry if I’m wrong
6 0
2 years ago
Two strings are respectively 1.00 m and 2.00 m long. Which of the following wavelengths, in meters, could represent harmonics pr
MrRissso [65]

Answer:

5) 4.00, 2.00, 1.0

Explanation:

wave equation is given as;

F₀ = V / λ

Where;

F₀ is the fundamental frequency = first harmonic

Length of the string for first harmonic is given as;

L₀ = (¹/₂) λ  

λ  = 2 L₀

when L₀ = 1

λ  = 2 x 1 = 2m

when L₀ = 2m

λ  = 2 x 2 = 4m

For First harmonic, the wavelength is 2m, 4m

For second harmonic;

L₁ = (²/₂)λ  

L₁ = λ

When L₁ = 1

λ  = 1 m

when L₁ = 2

λ  = 2 m

For second harmonic, the wavelength is 1m, 2m

Thus, the wavelength that could represent harmonics present on both strings is 4m, 2m, 1 m

6 0
2 years ago
A person who weighs 625 N is riding a 98-N mountain bike. Suppose that the entire weight of the rider and bike is supported equa
kozerog [31]

Answer:

A = 4.76 x 10⁻⁴ m²

Explanation:

given,                                  

weight of the person = 625 N

weight of the bike = 98 N        

Pressure on each Tyre = 7.60 x 10⁵ Pa

Area of contact on each Tyre = ?          

total weight of the system = 625 + 98

                                             = 723 N

Let F be the force on both the Tyre

F + F = W                                    

2 F  = 723                                    

F = 361.5 N                                

F = P A                                            

A = \dfrac{F}{P}                          

A = \dfrac{361.5}{7.60 \times 10^5}

A = 4.76 x 10⁻⁴ m²

7 0
2 years ago
The absolute pressure in water at a depth of 5m is read to be 145 kPa. Determine (a) the local atmospheric pressure, and (b) the
irga5000 [103]

Answer:

a) 95950 pascals

b) 137642.5 pascals

Explanation:

The absolute pressure (Pabs) on a fluid is:

P_{abs}=P_{gauge}+P_{atm} (1)

With Pgauge the pressure due depth on the fluid and Patm the atmospheric pressure. Pgauge is equal to:

P_{gauge}=\rho gh (2)

with ρ the fluid density, g the gravitational acceleration and h the depth on the fluid. Using (2) on (1) and solving for Patm:

P_{atm}=P_{abs}-P_{gauge}=P_{abs}-\rho_{water} gh

P_{atm}=(145000Pa)-(1000\frac{kg}{m^{3}})(9.81\frac{m}{s^{2}})(5m)

P_{atm}=95950Pa

b) Here we're going to use again (1) but now we have another value of density because it's other liquid, to know that value we should use the fact that specific gravity (S.G) for liquids is the ratio between fluid density and water density:

S.G=\frac{\rho_{fluid}}{\rho_{water}}

\rho_{liquid}=S.G*\rho_{water}

\rho_{liquid}=(0.85)*(1000\frac{kg}{m^{3}})=850\frac{kg}{m^{3}}

so:

P_{abs}=\rho_{liquid} gh+P_{atm}=(850\frac{kg}{m^{3}})(9.81\frac{m}{s})(5m)+95950Pa

P_{abs}=137642.5 Pa

3 0
2 years ago
Which correctly identifies the parts of a transverse wave? A: crest B: amplitude C: wavelength D: trough A: trough B: amplitude
jenyasd209 [6]

Explanation :

In transverse waves the particles are oscillating perpendicular to the direction of propagation of waves.

The uppermost part of the wave is crests and the lowermost part is troughs.

Wavelength of a transverse wave is defined as the distance between two consecutive crests or troughs.

Amplitude is the maximum distance or displacement covered by a wave.

So, crest, amplitude, trough and wavelength identifies the parts of a transverse wave.

9 0
2 years ago
Read 2 more answers
Other questions:
  • Which type of listening response includes the use of head nods, facial expressions, and short utterances such as "uh-huh" that s
    8·1 answer
  • A student bikes to school by traveling first dN = 1.00 miles north, then dW = 0.600 miles west, and finally dS = 0.200 miles sou
    6·1 answer
  • The voltage across the terminals of a 9.0 v battery is 8.5 v when the battery is connected to a 60 ω load. part a what is the ba
    11·2 answers
  • Takumi works in his yard for 45 minutes each Saturday. He works in the morning, and he wears sunscreen and a hat each time he wo
    12·2 answers
  • A sleepy student drops a calculator out of a window that's 20.7\text{ m}20.7 m20, point, 7, start text, space, m, end text off t
    10·1 answer
  • Suppose the rocket is coming in for a vertical landing at the surface of the earth. The captain adjusts the engine thrust so tha
    5·1 answer
  • Water initially at 200 kPa and 300°C is contained in a piston–cylinder device fitted with stops. The water is allowed to cool at
    12·1 answer
  • An electron is moving in the vicinity of a long, straight wire that lies along the z-axis. The wire has a constant current of 8.
    10·1 answer
  • In this experiment, you need to examine the idea of thermal energy transfer. Using a controlled experiment, what might a good qu
    12·3 answers
  • If Katie swims from one end of the pool, to the other side, and then swims back to her original spot, her average velocity is ha
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!