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2 years ago

How will you prove that a given colourless liquid is an acid

Chemistry

2 answers:

Dmitry [639]2 years ago

6 0

Answer:

1. Using Litmus papers. Litmus paper will turn blue if solution is acidic or it will turn blue if it is basic. ... If pH is below 7 or reddish then the given solution is acidic and if pH is higher than 7 or bluish then the solution is basic.

Explanation:

baherus [9]2 years ago

3 0

Answer:

Explanation:

One: You could mix a small sample of it with a reactive metal. Underline small. You should see gas bubbles being given up. Usually the bubbles are hydrogen.

Example : K + HCl ===> KCl + H2

Two: You could use an indicator to watch it turn color as it goes from acidic to neutral. Litmus will go from red to blue under these conditions.

Three: Those are the two safest ways. If you knew the acid was dilute, you could put a small (underline small again) amount on your tongue. If it tastes like orange juice, it is likely an acid. This is a test every textbook mentions. You should never do it under any circumstances.

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The pH of an acidic solution is 2.11. What is [H⁺]

BartSMP [9]

Answer:

denotes the molar hydrogen ion concentration

Explanation:

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2 years ago

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If 350.0 grams of Cr2O3 are reacted with 235.0 grams of elemental silicon, 213.2 grams of chromium metal are recovered. What is

bulgar [2K]

We calculate for the amount of chromium metal in the reactant by,
= 350 x (mass of Cr2/mass of Cr2O3)
= 350 x (104/152)
= 239.47 grams
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percent yield = (213.2 grams/239.47) x 100%
= 89%

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2 years ago

when switch s is closed positive ions will undergo 1) oxidation at electrode B 2) oxidation at electrode A 3) reduction at elect

stepladder [879]

Answer:

reduction at electrode B

Explanation:

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2 years ago

If Co(NH3)63+ has a λmax at 440 nm, calculate ΔE for the complex. A) 2.72 x 10-4 kJ/mol B) 4.52 x 10-2 kJ/mol C) 2.72 x 10 2 kJ/

riadik2000 [5.3K]

<u>Answer:</u> The energy of the complex is $2.72\times 10^2kJ$

<u>Explanation:</u>

To calculate the energy of the complex, we use the equation given by Planck which is:

$\Delta E=\frac{N_Ahc}{\lambda}$

where,

$\lambda$ = Wavelength of the complex = $440nm=4.40\times 10^{-7}m$ (Conversion factor: $1m=10^9nm$ )

h = Planck's constant = $6.624\times 10^{-34}Js$

c = speed of light = $3\times 10^8m/s$

$N_A$ = Avogadro's number = $6.022\times 10^{23}$

$\Delta E$ = energy of the complex

Putting values in above equation, we get:

$\Delta E=\frac{6.022\times 10^{23}\times 6.624\times 10^{-34}\times 3\times 10^8}{4.40\times 10^{-7}}\\\\\Delta E=2.72\times 10^{5}J=2.72\times 10^2kJ$

Conversion factor used: 1 kJ = 1000 J

Hence, the energy of the complex is $2.72\times 10^2kJ$

5 0

2 years ago

The Safe Drinking Water Act (SDWA) sets a limit for mercury-a toxin to the central nervous system-at 0.002 mg/L. Water suppliers

posledela

Answer:

The volume of mercury-contaminated water that has to be consumed to ingest 0.100 g mercury is 2.50 × 10⁴ l

Explanation:

Hi there!

First, let´s convert 0.100 g to mg:

0.100 g · (1000 mg/1 g) = 100 mg

The contaminated water has 0.004 mg per liter, then, we have to find the volume of water that contains 100 mg of mercury:

100 mg · (1 l / 0.004 mg) = 2.50 × 10⁴ l

Then, the volume of mercury-contaminated water ( at a concentration of 0.004 mg/l) that has to be consumed to ingest 0.100 g mercury is 2.50 × 10⁴ l

Have a nice day!

8 0

2 years ago

How will you prove that a given colourless liquid is an acid​

How will you prove that a given colourless liquid is an acid