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valentina_108 [34]
2 years ago
13

How many grams are in 2.3 x10-4 moles of calcium phosphate ca3(po3)2

Chemistry
1 answer:
Airida [17]2 years ago
6 0

Answer:

calcium phosphate has the formula Ca3(PO4)2, which has the mass of 310 grams/mol.

1 mol contains 310 grams

2.3*10^-4 moles contain  2.3*10^-4 * 310, which means 713*10^-4 grams, or 71.3 milligrams.

If you wrote the formula right and named the compound wrong, all you have to do is replace 310 with 278 and the answer will be 639.4*10^-4 grams, or 63.94 milligrams.

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Explain on the chemical structural basis why the products of the saponification reaction are soluble in water while the starting
aev [14]

Answer:

The description is outlined in subsection downwards and according to the query given.

Explanation:

  • Saponification seems to be a procedure that requires the conversion or transformation of fat, grease, or lipid by either the intervention of heating a mixture of aqueous alkali towards soap as well as an alcoholic. Soaps contain fatty acid salts, however, mono-fatty acids contain carbon atoms, such as sodium palmitate. Therefore, throughout the water, individuals were indeed soluble.
  • However, on another hand, owing to large hydrocarbon strings, triglycerides do not partake in hydrogen bonding. Therefore in water, they aren't dissolved.
7 0
1 year ago
1) How many aluminum atoms are there in 3.50 grams of Al2O3?
drek231 [11]

Answer:

Aluminium atoms =  4.13 *10^22 aluminium atoms

The correct answer is E

Explanation:

Step 1: Data given

Mass of Al2O3 = 3.50 grams

Molar mass of Al2O3 = 101.96 g/mol

Number of Avogadro = 6.022 * 10^23 /mol

Step 2: Calculate moles Al2O3

Moles Al2O3 = mass Al2O3 / molar mass Al2O3

Moles Al2O3 = 3.50 grams / 101.96 g/mol

Moles Al2O3 = 0.0343 moles

Step 3: Calculate moles Aluminium

In 1 mol Al2O3 we have 2 moles Al

in 0.0343 moles Al2O3 we have 2*0.0343 = 0.0686 moles Al

Step 4: Calculate aluminium atoms

Aluminium atoms =  moles aluminium * Number of Avogadro

Aluminium atoms =  0.0686 * 6.022 * 10^23

Aluminium atoms =  4.13 *10^22 aluminium atoms

The correct answer is E

3 0
2 years ago
Determine the normality of the following solutions note the species of interest is H 95 g of PO4 3- in 100mL solution
Aliun [14]

Answer : The normality of the solution is, 30.006 N

Explanation :

Normality : It is defined as the number of gram equivalent of solute present in one liter of the solution.

Mathematical expression of normality is:

\text{Normality}=\frac{\text{Gram equivalent of solute}}{\text{Volume of solution in liter}}

or,

\text{Normality}=\frac{\text{Weight of solute}}{\text{Equivalent weight of solute}\times \text{Volume of solution in liter}}

First we have to calculate the equivalent weight of solute.

Molar mass of solute PO_4^{3-} = 94.97 g/mole

\text{Equivalent weight of solute}=\frac{\text{Molar mass of solute}}{\text{charge of the ion}}=\frac{94.97}{3}=31.66g.eq

Now we have to calculate the normality of solution.

\text{Normality}=\frac{95g}{31.66g.eq\times 0.1L}=30.006eq/L

Therefore, the normality of the solution is, 30.006 N

5 0
2 years ago
Which of the following pairs lists a substance that can neutralize HNO3 and the salt that would be produced from the reaction?
Nutka1998 [239]

NH₃, being a basic gas neutralizes the HNO₃ forming a salt NH₄NO₃

Therefore the correct answer is NH₃ and NH₄NO₃

The solution of which only 32% dissociates to release OH⁻ ions is a weak base. This is because some of the energy is used when the substance reacts with the solution thus some bonds are not broken.

HCl is an acid. This is because it dissociates  in water to give H⁺ as the only positively charged ions.

Arrhenius acid increases the concentration of hydrogen ions because it dissociates to release hydrogen ions as the only positively charged ions in the acid. So the answer is TRUE

Arrhenius base dissociates in water to release hydroxide ions as the only negatively charged ions.

NaOH⁺aq⇒Na⁺ ₍aq₎+ OH⁻₍aq₎

5 0
2 years ago
If 32.0 g of MgSO4⋅7H2O is thoroughly heated, what mass of anhydrous magnesium sulfate will remain?
Arada [10]
Find moles of MgSO4.7H2O

molar mass = 246
so moles  = 32 / 246  = 0.13 moles.

When heated, all 7 H2O from 1 molecule will be gone. 
total moles of H2O present = 7 x 0.13 = 0.91
mass of those H2O = 0.91 x 18  = 16.38g

so mass of anyhydrous MgSO4 remain = 32 - 16.38 = 15.62 g
6 0
2 years ago
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