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BartSMP [9]
2 years ago
7

What is the momentum of a 50-kilogram ice skater gliding across the ice at a speed of 5 m/s? (1 point)

Physics
2 answers:
LenaWriter [7]2 years ago
4 0
P=mv
p=50kgx5ms-1
p=250
serious [3.7K]2 years ago
3 0
Momentum is a term used to quantify the motion of an object has. It is calculated as the the product of the object's mass and the velocity. It is expressed as:

Momentum = m x v
Momentum = 50 kg x 5 m/s
Momentum = 250 kg m/s

Therefore, the correct answer is the last option.
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The point on the graph that lies on the y-axis (vertical axis) is called the y-intercept. What does the y-intercept tell you abo
jekas [21]

Answer:

The starting position of the runner.

Explanation:

When you look at the graph, you can see that the first point on the graph is twenty on the y-axis.

The runner starts at twenty, and ends at thirty.

Therefore, the runner starts at twenty on the y-axis, so it's the starting position of the runner.

7 0
2 years ago
What is the mass of an object that creates 33,750 joules of energy by traveling at 30 m/sec?
nikklg [1K]
The Energy is Kinetic Energy.

Kinetic Energy = 1/2*mv²,  Where m is mass in kg, v is velocity in m/s

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1/2*mv² = E

1/2*m*30² = 33750

m = (2*33750) / (30²)     Using a calculator

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Mass of object is 75 kg.
5 0
2 years ago
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What is the net force acting on the buggy?<br> N<br> The net force is pointing to the...
blagie [28]

Answer:

390, right

Explanation:

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2 years ago
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before colliding, the momentum of block A is +15.0 kg m/s. after, block A has a momentum -12.0 kg*m/s. what is the momentum of b
Helen [10]

Answer:

The momentum of block B = 27 Kg m/s

Explanation:

Given,

The initial momentum of block A, MU = 15 Kg m/s

The final momentum of block A, MV = -12 Kg m/s

Consider the block B is initially at rest.

Therefore, the initial momentum of block B, mu = 0

According to the laws of conservation of linear momentum, the momentum of the body before impact is equal to the momentum of the body after impact.

                               <em> MU + mu = MV + mv</em>

                                15  +  (0) = (-12) + mv

                                         mv = 15 + 12

                                              =  27 Kg m/s

Hence, the momentum of the block B after impact is, mv = 27 Kg m/s

3 0
2 years ago
As a descending elevator approaches the correct floor, it slows to a stop with a constant acceleration of magnitude 1m/s*2. The
Nookie1986 [14]

Answer:

C

Explanation:

4 0
2 years ago
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