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-BARSIC- [3]
2 years ago
5

Numerous engineering and scientific applications require finding solutions to a set of equations. Ex: 8x + 7y = 38 and 3x - 5y =

-1 have a solution x = 3, y = 2. Given integer coefficients of two linear equations with variables x and y, use brute force to find an integer solution for x and y in the range -10 to 10.
Physics
2 answers:
Irina-Kira [14]2 years ago
6 0

Answer:

we do not have the integer coeficients, so the solutions may not be in the range -10 to 10 (it does not happen for all coeficients) so let's do other thing:

Ok, suppose you have the equations:

1) A*x + B*y = C

2) a*x + b*y = c

where A, B, C, a, b and d are knowed.

Let's solve them in the most general way, and you always can use those solutions in the future, just need to replace the values of the constants up there.

First, we isolate x or y in a equation, let's do it with x in equation 1:

A*x  = C - B*y

x = (C - B*y)/A

Now we can replace this in the equation 2, and solve it for y:

a*x + b*y = c

a*(C - B*y)/A + b*y = c

y*(b - a*B/A) = c - a*C/A

y = (c - a*C/A)/(b - a*B/A)

Now you have a solution for y, and we you know the value of y, you can put it in the eqution:

x = (C - B*y)/A

and find the value of x

mote1985 [20]2 years ago
5 0
Need help with this too
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Let u be the initial velocity of the soccer ball at an angle of inclination of \theta_0 with the positive x-axis.

Given that:

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Acceleration due to gravity, g= 10 m/s^2 downward.

As "north" and "up" as the positive x ‑ and y ‑directions, respectively.

So, g= -10 m/s^2

As the acceleration due to gravity is in the vertical direction, so the horizontal component of the initial velocity remains unchanged.

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Now,  u\cos(45^{\circ})=10 [as u_x=u\cos\theta_0]

\Rightarrow u=10\sqrt{2} m/s.

The vertical component of the initial velocity,

u_y= u\sin\theta_0

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Let v be the vertical component of the velocity at any time instant t.

From the equation of motion,

v=u+at

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v=u_y+(-10)t

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The vertical component of the velocity, v, is the function of time and related as v=10-10t.

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At 2 second, the vertical component of the velocity

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The graph has been shown in figure (ii).

7 0
2 years ago
In a power plant, pipes transporting superheated vapor are very common. Superheated vapor flows at a rate of 0.3 kg/s inside a p
grigory [225]

Answer:h=160.84 W/m^2-K

Explanation:

Given

mass flow rate=0.3 kg/s

diameter of pipe=5 cm

length of pipe=10 m

Inside temperature=22

Pipe surface =100

Temperature drop=30

specific heat of vapor(c)=2190 J/kg.k

heat supplied Q=mc\Delta T=0.3\times 2190\times (30)

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5 0
2 years ago
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-BARSIC- [3]
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<span> 1.440x10^6 g ( 1 kg / 1000 g ) = 1440 kg</span><span>
</span>
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Ket [755]

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2. Inelastic collision: When the momentum  the system is conserved but the kinetic energy is not conserved, the collision is said to be inelastic. For example, collision of a ball with the mud.

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