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Black_prince [1.1K]
2 years ago
8

Write a hypothesis that answers the lesson question, “While observing a chemical reaction, how can you tell which reactant is li

miting?” Hypothesis: If a substance is the limiting reactant, then . . . because . . .
Chemistry
2 answers:
IrinaK [193]2 years ago
4 0

Answer: If a substance is the limiting reactant, then it will be completely used by the time the reaction completes because it is the reactant that reacts completely and the reaction stops after it is completely used up.

Explanation:

Limiting reagent is a reagent as it limits the formation of product and Excess reagent is the reagent which is preset in excess.

For example: if 0.75 moles of HCl and 1.5 moles of magnesium are reacted together.

Mg(s)+2HCl(aq)\rightarrow MgCl_2(aq)+H_2(g)

According to stoichiometry:

As 2 mole of HCl reacts with 1 mole of Mg

0.75 moles of HCl will react with =\frac{1}{2}\times 0.75=0.38moles of Mg

HCl is a limiting reagent as it limits the formation of product and Mg is an excess reagent as (1.5-0.38)=1.12 moles of magnesium are left unreacted.

My name is Ann [436]2 years ago
3 0

Answer:  If a substance is the limiting reactant, then it will be fully consumed by the time the reaction completes because it is the reactant that reacts completely and the reaction cannot proceed further.

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Which is the first element to have 4d electrons in its electron configuration?
harkovskaia [24]
The first element to have 4d electrons in its electron configuration is Yttrium with an atomic number of 39 and the chemical symbol Y. The electron configuration of an atom refers to the distribution of its electrons in the atomic orbitals. These orbitals are represented by letters s,p,d,f and so on. The electron configuration of Yttrium is [Kr] 4d¹ 5s², wherein [Kr] refers to the electron configuration of the noble gas, Krypton.  
3 0
2 years ago
Menthol is a flavoring agent extracted from peppermint oil. It contains C, H, and O. In one combustion analysis, 10.00 mg of the
RideAnS [48]

Answer:

C₁₀H₂₀O

Explanation:

The molecular formula must be C_{x}H_yOz. The combustion reaction will occur between the fuel and oxygen gas:

C_{x}H_yOz + O₂ → CO₂ + H₂O

For Lavoisier law, the mass of the reactants must be equal to the mass of the products (mass conservation):

10.0 + mO₂ = 28.16 + 11.53

mO₂ = 29.69 mg

Supposing that all the oxygen and the menthol were consumed, let's calculate the number of moles of the compounds, knowing, for the Periodic Table, that:

MC = 12 g/mol, MO = 16 g/mol, MH = 1 g/mol

MCO₂ = 12 + 2x16 = 44 g/mol

MH₂O = 2x1 + 16 = 18 g/mol

MO₂ = 2x16 = 32 g/mol

n = mass (g)/molar mass

nCO₂ = 0.02816/44 = 6.4x10⁻⁴ mol

nH₂O = 0.01153/18 = 6.4x10⁻⁴ mol

nO₂ = 0.02969/32 = 9.3x10⁻⁴ mol

The molar number is proportional in the molecule, so, in CO₂, the number of C is 6.4x10⁻⁴ mol, and of O is 1.28x10⁻³. All the carbon of the methol will be in CO₂, and all the H will be in H₂O. The number of moles of O will be the difference of moles in H₂O and the O₂, then:

nC = 6.4x10⁻⁴ mol

nH = 2x6.4x10⁻⁴ = 1.28x10⁻³ mol

nO = (2x6.4x10⁻⁴ + 6.4x10⁻⁴) - (2x9.3x10⁻⁴) = 6.0x10⁻⁵

The empirical formula is the molecule formula with the small subscripts numbers, which represent the number of moles of the atoms in the molecule. So, let's divide all the number of moles for the small on 6.0x10⁻⁵.

nC = (6.4x10⁻⁴)/(6.0x10⁻⁵) = 10

nH = (1.28x10⁻³)/(6.0x10⁻⁵) = 20

nO = (6.0x10⁻⁵)/(6.0x10⁻⁵) = 1

So, the empirical formula of methol is C₁₀H₂₀O.

3 0
2 years ago
Which number is equal to -906,060?
Eva8 [605]

Answer:

it would be c

Explanation:

jshshsyyehdhdhdhdhdhhdhshdbdhdhfhdhdhdhd

7 0
2 years ago
Read 2 more answers
Write equations that show the processes that describe the first, second, and third ionization energies for a gaseous iron atom.
Nikolay [14]
The ionization energy of an element is the amount of energy required to remove one mole of electrons from the element in its gaseous state. The equations for the first three are:

Fe(g) → Fe⁺(g) + e⁻

Fe⁺(g) → Fe⁺²(g) + e⁻

Fe⁺²(g) → Fe⁺³(g) + e

7 0
2 years ago
A bottle of antiseptic hydrogen peroxide (H2O2) is labeled 3.0% (v/v). How many mL H2O2 are in a 400.0 mL bottle of this solutio
PolarNik [594]

Answer:

= 12 mL H202

Explanation:

Given that, the concentration of H2O2 is given antiseptic = 3.0 % v/v

It implies that, 3ml  H2O2 is present in 100 ml of solution.

Therefore, to calculate the amount of H202 in 400.0 mL bottle of solution;

we have;

 (3.0 mL/ 100 mL) × 400 mL

= 12 mL H202

6 0
2 years ago
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