The question is incomplete but the full question may be found in other sources.
This is the complete question:
- For the reaction 2Fe + 3Cl₂ → 2FeCl₃ which option is more accurate?
a. FeCl₃, reducing agent; Fe, oxidizing agent.
b. Cl₂, oxidising agent; Fe reducing agent.
c. Fe, reducing agent; FeCl₃, oxidizing agent.
d. FeCl₃, oxidizing agent, Cl₂, reducing agent.
Answer:
- <em><u>Option b. Cl₂, oxidising agent; Fe reducing agent.</u></em>
Explanation:
It is easy to recognize by simple inspection that the given reaction is a redox one (oxidation - reduction) because the substances in the reactant side are pure elements (whose oxidation state is always zero) and the substance in the product side is a compound formed by the two reactant elements (which means that now they have a different oxidation state).
In a redox reaction, <u>the element that increases its oxidation number</u> loses electrons and reduces other element, so this <u>is the reducing agent</u>. On the other hand, <u>the element whose oxidation number is decreased</u> has gained electrons, a so it <u>is the oxidizing agent</u> (it oxidizes other element).
I will show the oxidation states of each species in the chemical reaction, using superscripts:
- Fe⁰ + 3Cl₂⁰ → 2 Fe⁺³Cl₃⁻¹
Thus:
- 2 atoms of Fe increased their oxidation number from 0 to +3; meaning that they lost 6 electrons (3 electrons each), so Fe is the reducing agent (it reduced the Cl atoms).
- 6 atoms of Cl decreased their oxidation number from 0 to -1; meaning that they gained 6 electrons in total (1 elecron each), so Cl is the oxidizing agent (it oxidized the Fe atoms).