answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
podryga [215]
2 years ago
3

In the urea cycle, the second nitrogen of urea enters the cycle in the form of which of the following metabolites? A) Alanine B)

Glutamine C) Omithine D) Aspartate E) Arginine
Chemistry
1 answer:
k0ka [10]2 years ago
7 0

Answer:

In the urea cycle, the second nitrogen of urea enters the cycle in the form of <u>D) Aspartate .</u>

Explanation:

Urea cycle -

Also referred as the Ornitine cycle ,

This is biochemical pathway that can produce urea from ammonia . The urea cycle majorly takes place in the liver and few steps in the kidneys .

Steps involved in Urea Cycle are:

1. The formation of Carbamoyl Phosphate:

The process of the condensation of the bicarbonate ions along with ammonium ions that results in the formation of the carbomoyl phosphate , by the help of carbomoyl phosphate synthase -I enzyme that is present in the mitochondria of the liver .With the requirement of dicarboxylic acid  which is the N - acetyl glutamate and Magnesium ion , and requires 2 ATP .

2. Synthesis of Citrulline:

From the first step , the carbomyl phosphate formed now combines with the ornithine and synthesis cirtulline by using citrulline synthase as the enzyme .And the Citrulline can easily diffuse into the cytosol from the mitochondria .

3. Synthesis of Argininosuccinate:

Now in the cytosol , the Citrulline combines to amino acid aspartate and results in the formation of argininosuccinate , and the step is catalyzed by the enzyme argininosuccinate synthase . The step need AMP and Magnesium ion as the cofactor.  

4. Cleavage of Argininosuccinate:

Now, Argininosuccinase enzyme reversibly acts in order to cleave argininosuccinate to Fumarate and Arginine .

5. Cleavage of Arginine:

Under the influence of Arginase enzyme , Arginine is lysed to urea and ornithine .Therefore , arginine is referred as the semi - essential amino acid    

And lastly the Ornithine is regenerated and completes the Urea Cycle by the formation of Urea.

You might be interested in
The initial temperature of the water in a constant-pressure calorimeter is 24°C. A reaction takes place in the calorimeter, and
kupik [55]

Answer:

Explanation:

For a chemical reaction, the enthalpy of reaction (ΔHrxn) is … ... to increase the temperature of 1 g of a substance by 1°C; its units are thus J/(g•°C). ... Both Equations 12.3.7 and 12.3.8 are under constant pressure (which ... The specific heat of water is 4.184 J/g °C (Table 12.3.1), so to heat 1 g of water by 1 ..

8 0
2 years ago
Read 2 more answers
What is the percent yield of this reaction if 22.o g of Mgl2 is produced by the reaction of 25.0 g of Mg with 25.0 g of l2?
expeople1 [14]

% yield = 80.719

<h3>Further explanation</h3>

Given

22.0 g of Mgl₂

25.0 g of Mg

25.0 g of l₂

Required

The percent yield

Solution

Reaction

Mg + I₂⇒ MgI₂

mol Mg = 25 g : 24.305 g/mol = 1.029

mol I₂ = 25 g : 253.809 g/mol = 0.098

Limiting reactant = I₂

Excess reactant = Mg

mol MgI₂ based on I₂, so mol MgI₂ = 0.098

Mass MgI₂ (theoretical):

= mol x MW

= 0.098 x 278.114

= 27.255 g

% yield = (actual/theoretical) x 100%

% yield = (22 / 27.255) x 100%

% yield = 80.719

8 0
1 year ago
If the actual yield of the reaction was 75% instead of 100%, how many molecules of no would be present after the reaction was ov
artcher [175]
To be able to answer this equations, we must set given information. Suppose the reaction to yield NO is:

N₂ + O₂ → 2 NO

Next, suppose you have 1 g of each of the reactants. Determine first which is the limiting reactant.

1 g N₂ (1 mol N₂/ 28 g)(2 mol NO/1 mol N₂)= 0.07154 mol NO present

Number of molecules = 0.07154 mol NO(6.022×10²³ molecules/mol)
<em>Number of molecules = 4.3×10²² molecules NO present</em>
8 0
2 years ago
Read 2 more answers
How many valence electrons are in chlorodifluoromethane
Elis [28]
<span>Well... first, let's recognize that the chemical formula for chlorodifluoromethane is CHClF2. Count out how many valence electrons there are. C = 4, H = 1, Cl = 7, F (X2) = 14. Total is 26. Let's put C as the central atom, and put the other elements surrounding it. Draw a pair of electrons beach each element and the central atom. Then fill the halogen elements with 3 pairs of electrons each to fill their octets. Count out how many dots you have. There should be 26, making this the correct lewis structure! Remember, hydrogen doesn't have a full octet, only a maximum of two electrons.</span>
7 0
2 years ago
How could installing new technology, such as scrubber machines, affect the factories required to install them? Name a positive a
Sindrei [870]

Answer:

Installing new technology, such as scrubbers, in factories will decrease their harmful emissions. This helps improve the safety of the surrounding community and the workers. But this technology is expensive and requires time and effort to install.

Explanation:

Hope this helped :)

5 0
2 years ago
Other questions:
  • Tungsten is the metal used in the filaments of incandescent light bulbs. Naturally occurring tungsten consists of five isotopes
    7·2 answers
  • When metals combine with nonmetals, the metallic atoms tend to 1. lose electrons and become positive ions 2. lose electrons and
    7·2 answers
  • The nucleus of an atom is dense and positively charged. What was observed when positively charged particles were radiated onto a
    5·2 answers
  • A 10 ft diameter by 15 ft height vertical tank is receiving water (p 62.1 lb/ cu ft) at the rate of 300 gpm and is discharging t
    7·1 answer
  • Which of the following is an extensive property of liquid benzene?
    15·1 answer
  • Write chemical equations and corresponding equilibrium expressions for each of the two ionization steps of carbonic acid. Part A
    11·1 answer
  • A student placed 11.5 g of glucose (C6H12O6) in a volumetric flask, added enough water to dissolve the glucose by swirling, then
    12·2 answers
  • Challenge question: This question is worth 6 points. As you saw in problem 9 we can have species bound to a central metal ion. T
    7·1 answer
  • A sample of chlorine gas is held at a pressure of 1023.6 Pa. When the pressure is decreased to 811.4 Pa the volume is 25.6 L. Wh
    12·1 answer
  • Perform the following conversion: 6.1 × 103 K (the surface temperature of the Sun) to °F and °C. Pay attention to the number of
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!