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choli [55]
2 years ago
4

Calculate the mass of a proton (in kg) using the charge-to-mass ratio given below and its known charge. (The charge of a proton

is 1.602 ✕ 10−19 C and the charge-to-mass ratio of a proton is 9.579 ✕ 107 C/kg. Round your answer to at least four significant figures.)
Physics
1 answer:
ra1l [238]2 years ago
3 0

Answer:

1.672\times 10^{-27}kg

Explanation:

Given:

Charge-to-mass ration of a proton, \frac{q_p}{m_p}=9.579 \times 10^7 C/kg

charge of a proton, q_p=1.602\times 10^{-19} C

mass of the proton can be calculated as follows:

m_p= \frac{q_p}{q_p/m_p} = \frac{1.602\times 10^{-19}C}{9.579 \times 10^7 C/kg} = 1.672\times 10^{-27}kg

Thus, the mass of a proton is 1.672\times 10^{-27}kg

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Stolb23 [73]

Answer:

m = 0.111 kg

Explanation:

Heat required to release from the body of the person when his temperature cool down by 1 degree C is given as

Q = m s\Delta T

here we know that

m = 70 kg

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\Delta T = 1.00^o C

now we know that

Q = (70 kg)(3840 J/kg ^oC)(1 ^o C)

Q = 268800 J

now the same heat is used to vaporize water of the body

so it is given as

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7 0
2 years ago
A uniform Rectangular Parallelepiped of mass m and edges a, b, and c is rotating with the constant angular velocity ω around an
Sonbull [250]

Answer:

(a) k = \frac{Mw^{2} }{6} (a^{2} +b^{2} )

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Explanation:

The moment of parallel pipe rotating about it's axis is given by the formula;

I = \frac{M}{3} (a^{2} +b^{2} )   ---------------------------------1

(a) The kinetic energy of a parallel pipe is also given as;

k =\frac{1}{2} Iw^{2} --------------------------------2

Putting equation 1 into equation 2, we have;

k = \frac{M}{6} (a^{2} +b^{2} )w^{2}

k = \frac{Mw^{2} }{6} (a^{2} +b^{2} )

(b) The angular momentum is given by the formula;

τ = Iw -----------------------3

Putting equation 1 into equation 3, we have

τ = \frac{Mw}{3} (a^{2} +b^{2} )

But

τ = dτ/dt = \frac{M}{3} (a^{2} +b^{2} )\frac{dw}{dt}   ------------------4

where

dw/dt = angular acceleration =∝

Equation 4 becomes;

τ = \frac{M}{3} (a^{2} +b^{2} ) ∝

8 0
2 years ago
Two parallel wires carry a current I in the same direction. Midway between these wires is a third wire, also parallel to the oth
Luda [366]

Answer:

Force is repulsive hence direction of force is away from wire

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The first thing will be to draw a figure showing the condition,

Lets takeI attractive force as +ve and repulsive force as - ve and thereafter calculating net force on outer left wire due to other wires, net force comes out to be - ve which tells us that force is repulsive, hence direction of force is away from wire as shown in figure in the attachment.

4 0
2 years ago
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Assuming the starting height is 0.0 m, calculate the potential energy of the cart after it has been elevated to a height of 0.5
Bogdan [553]
The potential energy is most often referred to as the "energy at rest" and is dependent on the elevation of an object. This can be calculated through the equation,

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8 0
2 years ago
Turner's treadmill runs with a velocity of -1.3 m/s and speeds up at regular intervals during a half-hour workout. after 25 min,
Travka [436]

Given : Initial velocity = -1.3 m/s

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Solution: We are given units in meter/second (m/s).

So, we need to convert time 25 minutes in seconds.

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Formula for average acceleration is given by,

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Plugging values in the above formula.

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2 years ago
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